Joule Ringer!

[resonanceman]

That may be true Bill, and I may be one of them. Does anyone here understand the JT circuit and how it works?

At OUR, I've blown away the misconception that a JT functions by way of a saturated core, and I've spent a number of hours working on the problem of "how it actually works", but I've not yet come to a complete answer.

I'd be grateful if someone here could enlighten me.

Thanks,
.99

poynt99

This was posted quite a while ago
It is in my opinion the best description  of how a JT works that I have seen.

[Feynman]

That's a good description; best I've seen so far.   But it does not explain what happens when the circuit gets out of phase.

I snagged my trifilar joule thief  and my analog scope today... I'll be replacing the LED with a 1k pot to see how it effects the circuit's scope traces.

[Pirate88179]

That may be true Bill, and I may be one of them. Does anyone here understand the JT circuit and how it works?

At OUR, I've blown away the misconception that a JT functions by way of a saturated core, and I've spent a number of hours working on the problem of "how it actually works", but I've not yet come to a complete answer.

I'd be grateful if someone here could enlighten me.

Thanks,
.99

Well, that is an honest response and I will give you another.  I, for one, do not totally understand how this circuit works, and what it can really do.  My research and experiments thus far are documented, and others have replicated some of them.  I think Larry is a bit off on his measurements and hopes but, if he shows OU then I will be the first to congratulate him.

The main thing about the JT circuit that has bothered me from the start is that a lot of EE's kept claiming that this is well known and there is nothing new here.  OK, fine.  Then why can I rebuild a simple LED flashlight that took 3 AA's and run it on a "dead" AA that make the light brighter and last much longer than with the 3 AA's?

I have never, ever claimed OU with this circuit.  The only thing I am on record for is saying that I believe the JT circuit might be part of an actual OU circuit.  That is all.

Thank you for your intelligent response.  I appreciate it.

Bill

[teslaalset]

That may be true Bill, and I may be one of them. Does anyone here understand the JT circuit and how it works?

At OUR, I've blown away the misconception that a JT functions by way of a saturated core, and I've spent a number of hours working on the problem of "how it actually works", but I've not yet come to a complete answer.

I'd be grateful if someone here could enlighten me.

Thanks,
.99

Poynt,
The Joule Thief is nothing more than what is called a 'blocking oscillator'.
There is a massive amount of information on variations of the concept and the theory how these oscillators work.

Attached is reference book info that I use to understand the basics with very good detailed explanation.
This book is available on usenet, if you are familiar with downloading from usenet.
You also might try this link : http://www.mediafire.com/?6fp0pjli0dbyi3p and download it from there.
Blocking oscillators are explained from page 3-58 to 3-99.

_{Note: [in my country, the Netherlands,  downloading (e)books is legally allowed, you might check your situation first before doing so]}

[Mk1]

That may be true Bill, and I may be one of them. Does anyone here understand the JT circuit and how it works?

At OUR, I've blown away the misconception that a JT functions by way of a saturated core, and I've spent a number of hours working on the problem of "how it actually works", but I've not yet come to a complete answer.

I'd be grateful if someone here could enlighten me.

Thanks,
.99

I will give you my 2 cents , both coil have the same potential , when one coil is closed the bemf is induced in the second coil since they are out of phase ...

Mark

Btw the joule ringer is also working in that manner (the bifilar coil no one actually see the need for ) A clues is that with the same current direction the copper and the iron coil have opposite poles so the emf is in the same direction as the bemf of the opposite wire if the pair .