Shorting coil gives back more power

[penno64]

Bulb is just handy as a small load.

Penno

[yssuraxu_697]

Using the roughly wound microwave oven fan core, I was able to see what Romero has been saying.

Could you please clarify a bit.
You have 1 extra winding?
Original winding is shorted extra winding is loaded?

[penno64]

That's what I did.

Shorting original with reed and collecting from additionally wound coil.

Penno

[yssuraxu_697]

Shorting original with reed and collecting from additionally wound coil.

Ok, and when loading extra coil RPM did rise... But compared to what? All coils open or original winding being still shorted by reed (and extra coil open)?

[gyulasun]

Hi Oscar,

A light bulb surely has a self inductance but only in the some hundred nano or max a few microHenry range and considering the low frequencies involved here (if rotor speed is say 3000 RPM, the frequency is just 50 Hz) the resistive part of the wire inside the bulb is what mainly counts (some 10 to 100 Ohms versus the some 0.1 Ohm of series inductive impedance).

The only problem you may better be aware of is the resistive part is nonlinear.  This can be significant if you wish to make meaningful measurements: a voltage and current meter is a must for checking real power.  Light bulbs are very good for indicating output power increase or decrease while tuning a setup and always keep in mind they are nonlinear. Their inductive properties are negligible at such low frequencies.

rgds,  Gyula

Thank you penno64.
Are you using a lightbulb as a load on the pickup-coil?
Can it be that a lightbulb is more suitable to find the effect than a resistor or potentiometer/rheostat?

In other words: Is it easier to find the effect with a lightbulb as load, since the lightbulb has inductance (a lightbulb is a coil of sorts, after all)?

edit to add: and Inductance means, that the resistance of that inductive element varies with the frequency of the input signal.