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Overunity Machines Forum



The Gabriel Device, possible COP=8

Started by Feynman, March 22, 2011, 04:07:09 PM

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0 Members and 14 Guests are viewing this topic.

Mavendex

Thinking..... Manufacturing in the future me thinks  :-X

matthewklinko

Quote from: SchubertReijiMaigo on October 24, 2011, 09:27:49 AM
It's the same as the download section, 156/117, Yeah it's crazy this the exact same version,  input is 12 V 50Hz... I calibrated the scope used the same shunt (a telephone wire) for current measurement, same scales, etc,etc make several measure but not I find this curious result... I think it's due to the turn ratio less than one... If I remember correctly I 'am the one with turn ratio under one...
Hmm I think it's time to ad turns at secondary...

Hello SchubertReijiMaigo

I am getting the same results as you, and my scope shots look the same.
A lot more power required to power load then needed. And input PF is a little less then 1
I have 400 turns on my primary and 2000 turns on my secondary so looks like winding ratios dont really matter.

Can I ask what core you are using, and the permeability?

matthewklinko

Quote from: SchubertReijiMaigo on October 24, 2011, 12:40:00 PM
This is why I think about unconventional current like Radiant-Cold current. Many inventors and "Legend" tell that cold current cannot be measured by conventional meter but those current perform work like any other conventional current. Believe me, I 'am highly disturbed here, because normally nothing can trick an oscilloscope look like a fox prank for me  :D !!!

What do you mean by tricks oscilloscope ?

I have connected my toroid primary in series with a 240V 2000W Kettle.

I applied a voltage of 110V the results for no load are.

Kettle
26.5V   0.85A   22.26W

Toroid
86.8V   0.84A   72.9W

Total Power = 95.16W

Then I load the secondary with a 240V 60W globe:

Kettle
21.7V   0.68A   14.75W

Toroid
91.6V   0.68A   62.29W

Total Power = 77.04W

As you can see the total power dropped when I added a load.
But this is because the kettle is the current limiting device in my circuit.
Hence when I loaded the secondary the voltage across the primary increased, and hence
the voltage drop across the kettle decreased, hence also decreasing the current flowing.
The reduced current results in less power being consumed. (voltage constant)

I think this explains why you see visual results but the oscilloscope shows the truth.

SchubertReijiMaigo

QuoteWhat do you mean by tricks oscilloscope ?

Radiant or cold electricity, is not measurable with conventional meter...

For the result: IS your core is saturated what is your cross section ?
(This can explain the current drop at primary side, to understand this try to saturate a trafo and load it, you will see curious effect but no OU)

Mine is 3.24cm^2 and 30000µ.
Shield is 2 millimiter.

QuoteI have 400 turns on my primary and 2000 turns on my secondary so looks like winding ratios dont really matter.

Hmm, look like bad news here, if I can't switch in OU state by turn ratio, the last parameter is the thickness of the shield to switch PF to 0 at all load...


matthewklinko

Quote from: SchubertReijiMaigo on October 25, 2011, 05:05:48 AM
Radiant or cold electricity, is not measurable with conventional meter...

For the result: IS your core is saturated what is your cross section ?
(This can explain the current drop at primary side, to understand this try to saturate a trafo and load it, you will see curious effect but no OU)

Mine is 3.24cm^2 and 30000µ.
Shield is 2 millimiter.

Hmm, look like bad news here, if I can't switch in OU state by turn ratio, the last parameter is the thickness of the shield to switch PF to 0 at all load...

My core is 9cm^2 and it was measured to be 60000u at 20khz

Also interesting result when I doubled the load with two globes the current increased again to over 1A
So there may be something there ...