Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Hydro Differential pressure exchange over unity system.

Started by mrwayne, April 10, 2011, 04:07:24 AM

Previous topic - Next topic

0 Members and 171 Guests are viewing this topic.

parisd

MrWayne or others,

I am new to this thread and off course did not go through all the posts but I have a general question;
I read that the ZED has between 104 and 300% overunity depending of the number of layers but read also that there is no external input whatsoever not even compressed air so how is calculated the overunity?

it should be output/input but input is zero, so to what correspond the 100% if one layer gives 103%

tks

Dennis

neptune

@Parisd. I will have a shot at answering this. In order to lift, a Zed does need input, usually the injection of some water into the pod chamber. When the limit of lift [stroke] is reached, the contents of the zed are still under pressure. So as we release this pressure , we can make use of this pressure to partially pressurise another Zed. What corresponds to 100%? That would be  a simple Archimedes Buoyancy system.
  A two Zed system uses no external input , as the pressure is shuttled back and forward between the 2 Zeds. A percentage of the output power has to be used to aid this process.

polln8r

Quote from: TinselKoala on August 21, 2012, 08:12:47 AM
Oops. Looks like I forgot something...
;)

http://www.youtube.com/watch?v=khZtoyjF4aA

Interesting setup... difficult to tell what's going on through the dark green section. How does it work? And, hot glue's great for many things, but not so much for water-tightness (although, if you use enough it'll get you by ;)).


polln8r

fletcher

It's a combination hydraulic-pneumatic system [like being mentioned on this thread except without buoyancy] - overall there's a net reduction in system PE i.e. the system CoM lowers over time - PE of water is converted to KE of water & height achieved [PE] for a portion of that water.

The system PE is restored when the water is added at the top of the bowl - a kind of hydraulic clock that needs rewinding.

Not OU but shows looks can be deceiving & a bit of fun by TK.

TinselKoala

@webby, thanks, I thought the risers were sealed at the top, I just woke up and I don't quite understand yet what you  mean by 'feed tube' in the context of the risers.

In my original mental picture I thought your risers are only open on the bottom, and I thought that increased depth would force more water up the bottom, compressing the air but also reducing the displaced volume and hence also the lift force, just like the Cartesian diver.

I'll have to have some coffee and think about your numbers.
Again, thanks for indulging a silly old Koala.
---TK