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Overunity Machines Forum



Hydro Differential pressure exchange over unity system.

Started by mrwayne, April 10, 2011, 04:07:24 AM

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hartiberlin

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mrwayne

Quote from: mondrasek on June 08, 2012, 05:31:14 PM
@mrwayne, is the precharge method for introducing the air through the pipe into the pod (to pressure balance the static system) exactly the same when you are setting up the system to run by exchanging the water vs. exchanging the air?

Thanks,

M.

Sorry Men, + Ladies,
I have been super busy setting up tests.
Now that i am not having to spend so much time on nay sayers - lets get to the fun!
I see where the group has dwindled down to the experimentors - good, lets roll.
OK, the tube in the pod - no - it was when we were transfering the stored energy from one side (Zed tank) to the next the high tube kept the water from getting into the tube.
With the water moving - it is irrelevant - as well as the skirt under the pod - no need when moving water - make your pod full length.
I am still testing - but wanted to guide you on the model -
3 layers is the least effecient - (Over unity), 4 is not much better - build you model at least six layers -250% with two Zeds connected, 190% with one Zed.
Eight layers breaks 350% but new set of variables to deal with (head loss in the outer most layers must be mathced to volume at pressure) - six layers is pretty easy.
Next, be sure to have your upper surface above the water - like in the patent - with extension.
Make the holding tank tight clearnace - just like the layers - it acts as another head storage - big tank wastes it.
Conect the input to the center (bottom) - no elongated tube is needed - use water - not air.
Do not worry about the weight of the layers - it actually improves the system. the weights cancel out when two tanks are connected (why a two Zed system is better than one) - but holds the system in the "Travis Effect".
On that note - once you reach Determine the Ideal lift without weight divide that by three - Make sure your risers weigh that much (add weight) - we are only going to be producing "free" about a third of the total potential - assuming the best system can net the full "Ideal" is another big mistake made - then you have magical energy.
You must have resistance for the system to work - so you never apply work to the system without a load,
Without a load - the system leaves the "Travis effect" you entire operation will be inside of it.

Concerning the load - if you are using the system like a pump-  water up a tube - so the riser has to lift the weight of the water in the tube to a higher level - that is a good simple demonstration.
use the higher water pressure to operate your level arm - and you will have a perpetual water fall - you will need to design an over flow - that is what we did with out model 7, we just wasted the extra.
Oops I forgot - M. Mentioned the need for the lower seperator - called RIng walls in the patent - MUST have - without you are back to 37%.

I will give advice as you go, send pictures so I can advise.

My request - these are for personal use - I have an agreement working with a another party.

Two - you agree to put the name on all models "ZED" or Travis Effect..

Three, you must also make me a model - I may be willing to pay your flight to the full size model and
have you stand in front of the full size model for pictures.

Lastly - if you do this as a group effort - I will donate $2000 for materials. Should cover everything but your efforts.

Time to invent!
Wayne Travis

TinselKoala

In the third video, when setting the experiment up, does it take the exact same force to submerge the "archimedes cup" with the "3 ounces of air" in it, as it does to submerge the "travis effect" cup with the same amount of air in it?

The first video would seem to indicate that it does not; the TE cup would take a stronger push to submerge it.

Therefore.... there is stored energy in the system, like a compressed spring, and this spring is compressed more on the TE side than on the other side.

When both cups are held down with the same amount of weight in the third video, the TE cup is effectively "lighter" in the water already, so when the air is bubbled into it, of course it rises first.... as long as the block is displacing some air. If the original water level was higher, the TE cup could rise up until the block no longer displaces air, and then ... except for the head start given by the stored energy ... the two cups will rise equally.

Why does this effect occur? I think it is because volume is conserved (or rather, pressure times volume is conserved for a gas) but surface area is not. This means that the gas pressure in the TE cup is greater than in the archimedes cup, even though they both started out with the same volume of gas initially. The gas in the TE cup is compressed more than the gas in the archimedes cup, because a lot of it is forced to a greater depth in the water by the displacer. This compression is stored energy, it requires work, this work is done when the cup is pushed down over the displacer _raising the water level in the external container_ and this work will be returned, minus losses, when the residual weight is further reduced by bubbling in the air from the bottom.

I think this explanation could be tested by linking the two submerged cups with a passive air tube across the air chambers, so that the pressures within them would be the same. (Test to make sure by seeing if it takes the same amount of weight to hold the cups down equally. If not... then there is asymmetric stored energy still.) Then bubble air into them from beneath as before.


neptune

Quote from: neptune on June 08, 2012, 03:16:40 PM
OK.At this stage we need to make a sort of mental "Block diagram" of what is required to build this model . Here are my initial thoughts.
1 A tank of water.
2 A "block" of 3 concentric cylinders . Need not be transparent in the mark 1 model , use empty food cans.
3 Some kind of frame or lever system to allow[2] to rise and fall a fixed amount without falling over .
4 a flexible tube to connect [2]  to [5]
5 A pump to force water or air as required into [2]. This could consist of a large vertical hyperdermic syringe .
  By pushing it down with a weight , we can measure input energy [weight x distance it falls. ]


By causing [2] to raise a weight, we can measure output energy. [weight x distance it rises.]

  Until and unless we can, by the above methods, show that output exceeds input, it would be futile to proceed further in our attempts to build a self runner .


Anyone agree, disgree? Comments? Total cost thus far less than 10 dollars?
OK in the light of further info it is time to update the above list. First item 1. I had sort of envisaged putting 2 into a tank, e.g. an aquarium . Bad idea. The tank, should of course be the largest diameter cylinder of 2.
Now item 2 . I referred to this as a block . What I meant was block, as in block diagram, in electronics . So on a diagram you might have a square box or block labelled "Oscillator" . So we know what it does , but we do not concern ourselves with the individual components within . Yesterday , i did not fully understand how these cylinders were arranged , so I called it a block .


Here is my current understanding of this block . Imagine you have three empty baked bean cans . They are all the same height . Their diameters are , 6 inches ,5 inches and 4inches . Put some glue in the bottom of the 6" can, and drop the five inch can inside it. so they are concentric .Drop glue into 5" can , and place the 4" can inside it . Now we have 3 more cans , with diameters 5.5 , 4.5 , and 3.5 inches diameter . We glue these together to form a similar unit to we made with the first 3 cans . We invert this second unit and drop it into the first unit , so that the cans of the second unit interleave with the cans of the first unit . Before we drop it in , we fill the lower unit with water .  Can someone confirm , or deny , that this is the basic layout please? I know we can not use food cans because the gaps between adjacent cans needs to be smaller than half an inch .
      If my description above is correct , I can now understand the bit about the coiled hosepipe with the lower half of its turns filled with water .
      As with any new concept it is vital that we understand the basics or we will never grasp the complex. You can not do simultaneous equations unless you can add 2+2 . I am making progress I hope, but do not fully understand it yet . I am sure I am not alone .


Question . Is the upthrust or buoyancy of a given volume of air dependent on the SHAPE of that volume, and is that upthrust greatest when that volume is elongated in a vertical direction?


  Participation without a full understanding is futile.


  Momma always told me that two Zeds are better than one !