Hydro Differential pressure exchange over unity system.

[mrwayne]

Thank you for your concern.
We completed the closed looped system in November last year.
We just finished our Data collection/Alpha Model.
It was the best use of our money ;-)
Buoyancy is caused by pressure diffirentials x surface area - not by volume
Archimede's describes the "least amount of lift from a volume of air" much overlooked, which is what the "Travis Effect" demonstrates.
Wayne

[neptune]

Either I am thick, or I am missing something here. There are two inverted vessels in a tank of water. Both contain air, one is about three quarters full of air, the other contains only about one twentieth as much air . Both are prevented from floating to the surface by a two pound weight. You could have a third vessel with no air in it at all, that is,full of water. It too could be held in position by a two pound weight. What would that prove?
        Please will someone help me to understand what is being claimed here.

[mrwayne]

Not thick, just missed the key point.
Look closely at the begining of Tom's second Video, be careful to notice the Repulsive force he describes.
That force is proportional to the total lift in the container with 24 oz of air.
In your example 'the weight on a cup filled with only water' does not have the repulsion.

[MileHigh]

Wayne:

The problem with your system is that the repulsive (or buoyancy) force in the inverted glass with the very small amount of air in it is not the same as the repulsive force in the glass that is filled with air.

The glass that is filled with air provides this repulsive force for the full travel of the glass from the bottom of the aquarium to the top of the aquarium.

The glass that has the small amount of air in it provides the large repulsive force as long as it does not move upwards.  The moment it starts to move upwards the repulsive  force starts to decrease rapidly.  After the glass has moved upwards about one centimeter, then the "extra" repulsive force is all gone.

So the glass with the small about of air in it can only do a small fraction of the buoyancy-related work (upwards force x displacement) as compared to the glass that is filled with air.

MileHigh

[johnny874]

Wayne:

The problem with your system is that the repulsive (or buoyancy) force in the inverted glass with the very small amount of air in it is not the same as the repulsive force in the glass that is filled with air.

The glass that is filled with air provides this repulsive force for the full travel of the glass from the bottom of the aquarium to the top of the aquarium.

The glass that has the small amount of air in it provides the large repulsive force as long as it does not move upwards.  The moment it starts to move upwards the repulsive  force starts to decrease rapidly.  After the glass has moved upwards about one centimeter, then the "extra" repulsive force is all gone.

So the glass with the small about of air in it can only do a small fraction of the buoyancy-related work (upwards force x displacement) as compared to the glass that is filled with air.

MileHigh

  MileHigh,
Am willing to bet you that if a colored liquid were poured into the bottom of his containers that it would show there is a depression around them. This depression would ensure that the there is a flat bottom for them to stand on. You know, other wise they might tip over if filled with your favorite refreshment. You can tell this by the curvature at the bottom.
But pushing air downwards is not trick. While he mentions ounces, it would actually be if he were using a liquid of that volume.
""many air-density tables state the density of dry air to be 1.25 kg/m³. That's equal to 0.000 722 546 ounce/cubic inch.

Read more: http://wiki.answers.com/Q/What_is_the_volume_of_air_that_weighs_one_ounce#ixzz1vhiYNqNh