Hydro Differential pressure exchange over unity system.

[mrwayne]

"The glass that has the small amount of air in it provides the large repulsive force as long as it does not move upwards.  The moment it starts to move upwards the repulsive  force starts to decrease rapidly.  After the glass has moved upwards about one centimeter, then the "extra" repulsive force is all gone."
You are right, very wise, My invention solved this, as well as a few you have not yet commented on 

Wayne

[johnny874]

"The glass that has the small amount of air in it provides the large repulsive force as long as it does not move upwards.  The moment it starts to move upwards the repulsive  force starts to decrease rapidly.  After the glass has moved upwards about one centimeter, then the "extra" repulsive force is all gone."
You are right, very wise, My invention solved this, as well as a few you have not yet commented on 

Wayne

  Correct me if I'm wrong but you're relying on hydraulic theory. ie., if a tube has a surface area of 10^2" and has 10 lbs. of force applied to it, then it has a lift potential of 1lb. per ^2 inch. And if the surface area is reduced to 5^2", then it has the potential of 2lb. per ^2 inch, right ?
With your demo, once lift has started, the surface area changes because the insert does not rise with the vessel being lifted.
It's funny though. With what I am working on, I can pump 2 lbs. of water over 20" high with a 1 lb. weight dropping 4 inches.
Still, I am after a working device (Bessler's Wheel) and not merely a demonstration of known theory. After all, hyraulics is used in many fields to multiply force well above what most people would think is achieveable. Even pneumatics is used which is merely air or an inert gas replacing a liquid which is not compressible.
@All, a pic of how containers are designed for mass production to ensure they are stable.

edited to add; almost missed it myself, oops   
Since the air is being compressed by the water in the tank, by decreasing the surface area of the water acting on it, it decreases on a proportionate scale the work it can do.
This simply means the insert reduces the work the compressed air can do so it has no advantage over not using the insert. Why it can't possibly work.

[hartiberlin]

Here is now the video of the Wayne Travis ZED device in action:


http://www.youtube.com/watch?v=cSy_33t86gc


It was first shown in the last Smartscarecrow show last Thursday night.

Regards, Stefan.

[TinselKoala]

MrWayne: I have a few questions. First, is there a video of your device in operation for a reasonable amount of time, powered or unpowered?

Next, some particulars:

Does your device require an external source of power? For example, do you need to run a compressor to store some compressed air, are there water pumps running, is there a big battery or a mains connection?

For how long does it "run" when it is not attached to an external power supply, including a tank of compressed air?

When it stops, why (or how) does it stop? Is a reservoir depleted, has the friction become too great, or like that. Or does it simply keep on running when it's disconnected from its power source? If the latter, PM me and I will start piling money into the armored car to bring to you.

These are questions concerning the current operation of a real device, not the theoretical predictions of how it will perform once you've got the kinks worked out. Do you have a "self runner" now, that requires no continuing source of external power, yet it continues to operate, producing useful work?



Now I also have some "theoretical" type questions about the demonstration of the cups in the aquarium and the operation of the system.

You do realise that whenever you do the work to submerge a volume of air, you also are _lifting_ an equal quantity of water an equivalent height, right? In fact it is raising this water that causes the "repulsion" you feel when you are pushing the air-filled cup down in the water: you are lifting a cup "full of water" to the top of the aquarium.

Now, imagine a spherical glass ball with a large hole in the bottom, like your cup but only spherical. Fill it with water and submerge, placing the weight on top. Now bubble air into it from underneath until it is neutrally buoyant. You now have "lift" that is equal to the weight. Right?
What happened to the water you displaced with your bubbles? If you carefully note the water level of the external container, you will find that it has risen, from its low point when the sphere was full of water, to a higher point now that the sphere is full of the air you pumped into it. In other words, when you pumped the air into your chamber, you pumped an equal quantity of water OUT, all the way up to the top of the external container. This represents stored energy. It is in the water that you lifted, NOT so much in the air.
Now.... introduce a balloon into your neutrally buoyant sphere of air. Start pumping WATER into the balloon, displacing the air in the sphere. Does the sphere become more buoyant during this process? What happens to the water level in the external container when you do this?
Or.... don't use an inner balloon or a pump at all, just make a little leak in the top of the sphere. As the air runs out and water runs in....  does the sphere become more buoyant during the process? What happens to the water level in the external container when you do this?

Thanks in advance--
--TK

(Yes, that's right, the disinformation campaign that has been trying to keep me distracted and confined to a single thread is breaking down and I am escaping once in a while to check activity in the "real world" of PM motors, buoyancy drives, gravity wheels and functionless electronic circuits.)

[hartiberlin]

Yes Wayne, would be interesting to know if the shown ZED device in the posted video:

http://www.youtube.com/watch?v=cSy_33t86gc

is still having external valves control via external batteries or grid power and
what is the total input energy this way and what is the total output energy.

Many thanks.

Regards. Stefan.

P.S: I have merged the 2 threads about it now into this one.