Hydro Differential pressure exchange over unity system.

[neptune]

@KanShi. Yes I understand basic mathematics and physics. What I would like you to do next is to draw two of the machines you illustrated in your last post, coupled together in such a way that the resulting machine would run itself and produce 500 Watts of surplus energy to power a load. Forget Physics and mathematics , there are only two possible scenarios here .


1 Mr Wayne Travis`s machine does what it says on the tin.


2 Mr Wayne Travis is either a conman, or is deluded, and has spent many years a half a million dollars developing one of the best conjuring tricks in the history of the world.  So good in fact that it has fooled Mark Dansie, and scores of other professional engineers.


3 There is no third possibility.


In the fullness of time we shall know one way or the other.

[KanShi]

@webby1: I have used the same formula as in the spreadsheet.
@neptune: My take is it's option 2 (it becomes obvious as soon as you simplify the device).

Although, if you want to build the device to see for yourself, go ahead. Building stuff is fun regardless of results.

[LarryC]

@KanShi,

Now, I understand that your issue is with the concept of water head. The pressure in your drawing is not 14.4, it is 3.6. The actual water head is the short distance from the top of the water column outside the riser to the top of the water in the riser. It is gravity that create the force, it is pushing down on both columns, and it does not matter if the volumes are different.

Regards, Larry 

[KanShi]

The piston is static (it does not move). To every action there is always an equal and opposite reaction. So the air inside the pod exerts pressure on the piston and the piston exerts pressure on the air.
The result is that the pod displaces the same amount of water as if the piston wasn't there - although only using a fraction of air volume (and also limiting the lift distance - but the same is true for the ZED from the patent).
Lift of the pod (with the stated parameters) is 3448 pounds (pi*(34.9/2)^2*100*0.03606) and the riser's lift is 15410 pounds (pi*(34.9/2)^2*14.4) => the total lift is 18858 pounds.
I am just talking about the lift force. Not sure what you mean by hydraulic lift (since the risers are basically hydraulic/pneumatic lifts (or lifters?) and they are part of the spreadsheet).

[Magluvin]

Lets say we have a closed bottom tube, and an empty top and bottom closed tube containing just air, that when it is inserted into the open top tube, we have say 1/8 in gap between the inner tube wall and the outer tube wall.

We fill the larger tube say 1/3 water.  We insert the floater in the tube containing the water.

By just the weight of the floater we should see some of the water forced up into the 1/8 in gap. Now we add weight/load. Say we add just enough to get the floater to just be hitting bottom. The 1/3 water may need adjustment as to not completely fill the 1/8 gap when the floater hits the floor. ;] lol floater.


Now we see there is more of the 1/8 in gap filled with water and the buoyant cylinder has just enough added weight to allow the cylinder to touch the bottom.

Now, if we add water to the gap, the loaded cylinder should rise. Of course as it rises, water needs to be taking up the displacement happening at the bottom at the inner cylinder rises.

So as we fill the gap, the loaded floater rises, and water added to the gap ends up filling space created by the rising loaded floater.

If we have 2 of these, exchanging the water levels from one floater set to the other, may be easier than lifting and lowering the loads manually.

Just my take on this so far. ;]

Mags