Hydro Differential pressure exchange over unity system.

[MT]

Hi guys,
sorry for jumping into discussions.


I would like to share something important.


There is OU in ZED and I can prove it now. For evidence I modeled single pod in cylinder (0 layer ZED) and calculated the work the pod can deliver and also work done while injecting water at bottom.
I think this is another OU aspect (diamond as MrWayne calls it) of Zed tech next to the aspect of exhaust reuse (the still discussed ABCD diagram).


So how to get it?
Remember still the travis effect video? 2 cups under water, air in between, pretty much feelable resistance when air is around the pod? Now take the cups out of water and dry your hands you wont need to get them wet again    Place cup on table and pod into it. Hold pod for while you pour water inbetween cup and pod until water reaches the top of the cup. This is precharge. Now stroke step. Release pod and allow it travel e.g. 1cm. Water level falls down quickly but you add water to the top again. My OU claim is when you have right gap and right dimensions of pod versus cup you will spent less work putting water in then the work done by the lifting pod.  Putting water from top is lossy as first you need to raise it and it falls down. Injecting water from bottom is tricky in the sense that water injected increases water head at bottom against which you need expend work while injecting new water. But it is solvable.


So what would you say of COP 3.41
for the cup of diameter and height 1m and pod diameter 0.98 m (1cm gap) with height 0.9m. Stroke length 10cm.


stay tuned...


respect,
Marcel

[MT]

Hi,


attached is spreadsheet calculating work spent and work done for particular dimensions of pod and cylinder. You can play with values and see what COP you get.


Work spent is calculated in iterations. Each iteration calc work needed to lift existing water over certain height + work needed to insert new water over the same height. More iterations = more precision. Currently have 10 and 30. Results converge to a certain value. Using too much iterations have on other side also negative  effect as rounding error gets bigger and bigger.


So OU is reality, hope it is clear now. Do not know how to make it clearer. If you find some bug in sheet pls let me know. I'm confident results are accurately representing reality but of course cannot guarantee 100%.


So seamus your 50k offer still valid? 


respect,
Marcel

[mondrasek]

@TK,

If you will, please visualize two open top cylinders of equal proportions at equal heights both filled 1/2 way with water.  A siphon tube is fixed inside of each very near the bottom and the tube is also primed and therefor full of water.

Now the cylinder on the left is allowed to drop 1/3 of its height, performing work.  During this change in height water is siphoned from the right cylinder over to the left cylinder so that the level of the water in each remains the same, correct?

Now work is done to raise the left cylinder back to its original height.  During this change in height water is siphoned from the left cylinder over to the right cylinder so that the level of the water in each remains the same, correct?

Neglecting the losses due to friction (standard ideal case assumption), what is the sum total of the work that was performed on the left cylinder during the entire cycle described?

M.

[TinselKoala]

@TK,

If you will, please visualize two open top cylinders of equal proportions at equal heights both filled 1/2 way with water.  A siphon tube is fixed inside of each very near the bottom and the tube is also primed and therefor full of water.

Now the cylinder on the left is allowed to drop 1/3 of its height, performing work.  During this change in height water is siphoned from the right cylinder over to the left cylinder so that the level of the water in each remains the same, correct?

Now work is done to raise the left cylinder back to its original height.  During this change in height water is siphoned from the left cylinder over to the right cylinder so that the level of the water in each remains the same, correct?

Neglecting the losses due to friction (standard ideal case assumption), what is the sum total of the work that was performed on the left cylinder during the entire cycle described?

M.

Didn't Wildew, fletcher and I already do this problem? Your splitting things up into "left cylinder" is again disingenuous, because the work done is actually on the water in the right cylinder as its level rises. You _could_ view the lifting of the water in the first cylinder as being "for free" since the PE doesn't change, due to the volume (mass) changing as the height is increased. However this is mistaken. You are increasing the total PE of the entire system when you lift, but it is hidden if you only consider the "left cylinder".  The siphon, once primed, is just like the underslung tube in its working and effect. The work you get out when you lower the left cylinder and let water run into it through the siphon must be replaced by raising the left cylinder to get things back to the start point.

[TinselKoala]

@MT: