PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[Magluvin]

My question has always been this:

Why must the load be a diode or LED? Can the load not be a pure resistance?

.99

Lol, why dont you?   

Mags

[Rosemary Ainslie]

Dear Professor,

I'm sure you'll forgive me taking this thread a tad off topic again.  But for reasons that I can't understand Harti has seen fit to lock my thread.  Which means this is the only place that I can reach you.  I see you've been wrestling with some test that may be definitive - as it relates to our claim.  I've outlined one such - that was carefully designed by our experts at BP some years back.  In any event - this most certainly IS definitive.  And although the test is different - the principle is the same.

One of the consequences of that early closure of my thread is that our challenge to you and Poynty Point may be misconstrued as being 'off the table' so to speak.   May I assure you that it is NOT.  I've detailed my challenge in the attached link.  And you may answer me through OUR.com.  I think they've got a thread there related to our claim. 

I know how anxious you are to promote over unity.  And I trust that our own modest efforts may have some kind of relevance to science generally and to unity breaches in particular.

Kindest regards Professor,
Rosie
http://newlightondarkenergy.blogspot.com/2012/02/255-challenge.html

[poynt99]

Lol, why dont you?   

Mags

Your response doesn't make sense. Did you mean to quote the next post?

If so, I'm chiming in late here, so I am not aware of what the latest circuit is that you were just discussing, re. the "current resistor".

The reason I ask about the replication minus the diode/LED, is because in my experience with JT's, they don't seem to work that well (or at all in some cases) without them.

What has your JT experience shown in this regard mags?

[Magluvin]

Poynt, its getting twisted here.

You said why a diode for a load, in response to Prof quote that was in agreement with me.

Either you didnt see what was posted, which was why I replied to you, or , you disapprove of the Prof agreement with me, about just using a resistance as a load, just as you said in your post?     What is the beef?  Dang.

Then you want me to describe a circuit that you propose as the way to do it?     

What that all about?   
Mags

[poynt99]

Either way, if using the current resistors, measuring the resistor for power out would be the best bet.

Mags

If it is implied that a diode or LED is still used ALONG WITH the "current resistor", then you are still using a diode or LED, correct?

If that is correct, then you are still using a diode or LED as part of the load, and just measuring the power in the "current resistor" is NOT going to give you an accurate measurement of Pout.

Now, if I am assuming incorrectly with the above, then please correct me. If not, then I am not twisting things, I'm simply trying to get clarity regarding the reference to "current resistor".