PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[bolt]

Chris,

Using your test setup with my Rigol DS1052E scope taking average voltage readings across 1R resistors, I get 3.5mA I/P and just under 1.0mA O/P. In power terms this gives an efficiency of around 30%. My Rb is 56K and running frequency is 2.63MHz. Load is 1K. Battery supply voltage 3.0V.

Hoppy

But did you measure the o/p voltage? You must measure volts and amps. In OU phase shift creates reactive power increases voltage drastically! ZPE enters equation where current node is Zero not nothing while voltage is max.  High impedance load will appreciate this extra voltage @ 1mA could easy be 25v RMS from 3v supply. Larger unmatched loads creates phase shifts losses back below Over-unity.  This explains why high impedance florescent lights easy lit full brightness as OU JT far brighter than normal DC i/p.

[Tudi]

it's amazing how many people talk about RC components of a circuit while L is just characterized by number of turns most of the time. I think that L can have at least as much details as a C. How about wire resistance ? Inductance, Ferite type, size of the cavity, wire length, wire diameter, distance between wires, the way the coil was made ( wire direction ), how compact is your coil, the speed and amount of characteristic changes of the wire when gets heated.....
To get a perfect resonance you need to match quite a few details. No wonder most people are unable to reproduce devices if description is like : you need a 2 wire coil

I think it would be very wise if next step would be to create additional 2 circuits like the first one by Joulseeker and try to use the output of circuit 1 to feed circuit 2 and 3.

This would help regarding scaling details ( sum of output power...) + might reveal small details regarding the build that might have got missed in the description.

[Hoppy]

Post deleted

Hoppy

[Hoppy]

But did you measure the o/p voltage? You must measure volts and amps. In OU phase shift creates reactive power increases voltage drastically! ZPE enters equation where current node is Zero not nothing while voltage is max.  High impedance load will appreciate this extra voltage @ 1mA could easy be 25v RMS from 3v supply. Larger unmatched loads creates phase shifts losses back below Over-unity.  This explains why high impedance florescent lights easy lit full brightness as OU JT far brighter than normal DC i/p.

I've re-taken measurements and now have 1.80mV across the output shunt and 2V across the 1K load resistor, so the two match up reasonably well with the difference being down to the accuracy of my 1R shunt which has 5% tolerance.

Yes, 25V RMS at a particular load but not at 1K with my setup.

Hoppy

[jmmac]

Hoppy,

If you eliminate the 1 Ohm resistor and keep the 1K load, then you can just measure the voltage drop in the load and calculate the current and power. You should have more accurate values this way.

Jaime

I've re-taken measurements and now have 1.80mV across the output shunt and 200mV across the 1K load resistor, so the two match up reasonably well with the difference being down to the accuracy of my 1R shunt which has 5% tolerance.

Yes, 25V RMS at a particular load but not at 1K with my setup.

Hoppy