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Overunity Machines Forum



PhysicsProf Steven E. Jones circuit shows 8x overunity ?

Started by JouleSeeker, May 19, 2011, 11:21:55 PM

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yssuraxu_697

Since I'm persistent *********** I repeat the question:

"BTW When using very large capacitors, is capacitive reactance considered? For example 40000uF has Xc=10e-7ohms at 4Mhz."

In plain english: LARGE CAPACITORS ARE SHORT CIRCUIT FOR HIGH FREQUENCY.

So how you expect to loop this with 40KuF caps? Or is this intentional feature?

nul-points

Quote from: yssuraxu_697 on May 31, 2011, 07:03:39 AM
Since I'm persistent *********** I repeat the question:
[...]

hi

it's evident from the Prof's last few posts that he has been, and will be, busy with family commitments for a while

maybe you can add 'patience' to your list of virtues?  ;)

greetings
np


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yssuraxu_697

Quote from: nul-points on May 31, 2011, 07:35:23 AMmaybe you can add 'patience' to your list of virtues?

On the contrary. I think most people here are too patient reading endless pages of near-pointless arguments while paying no attention to fundamental issues with designs :)

Good example is Rosemary's thread. What was SNR ratio there... 5%?
Do we want research forum or pub here?

Nobody will post the "good stuff" on the pub wall you know.

xee2

Quote from: yssuraxu_697 on May 31, 2011, 07:03:39 AM
Since I'm persistent *********** I repeat the question:

"BTW When using very large capacitors, is capacitive reactance considered? For example 40000uF has Xc=10e-7ohms at 4Mhz."

In plain english: LARGE CAPACITORS ARE SHORT CIRCUIT FOR HIGH FREQUENCY.

So how you expect to loop this with 40KuF caps? Or is this intentional feature?

Large capacitors look like short to high frequency but they still charge and discharge with each cycle. The problem with large capacitor is that the internal resistance increases with frequency thus they have more energy lost per cycle to the internal resistance as frequency increases. You may need to do some research to understand that. In the self running Joule thief circuit I posted, the capacitor is at DC because the diode converts the AC to DC.

JouleSeeker

Quote from: yssuraxu_697 on May 31, 2011, 07:03:39 AM
Since I'm persistent *********** I repeat the question:

"BTW When using very large capacitors, is capacitive reactance considered? For example 40000uF has Xc=10e-7ohms at 4Mhz."

In plain english: LARGE CAPACITORS ARE SHORT CIRCUIT FOR HIGH FREQUENCY.

So how you expect to loop this with 40KuF caps? Or is this intentional feature?

As noted above, I do not intend to use the output without some kind of rectification;  I wrote above:

Quote
So I think we have a straightforward way to measure the input power Pin without an oscilloscope, using a cap and a stopwatch.

Measuring Pout will be more difficult.
On the output leg of the circuit, the voltage shows large swings, typically 12 V or so Vpp.  One could put a rectifier in this output leg, then charge a cap...  As long as that did not adversely affect the circuit performance.

I am interested in finding a reliable way to measure output Power, without using an oscilloscope.

It is true that I attempted to loop the power back from the output leg, but this was a preliminary effort after some rectification-- and I have not had time to pursue this nor have I presented even preliminary results from that effort.  It is on hold as I prepare for the imminent long trip.

The results provided above were with the four caps charged to a voltage which I told you, measured, then connected into the circuit to provide the input-voltage, in place of the battery.  This was not the circuit in which I attempted to loop power back -- just the DUT discussed by me in posts 1&2.  After each 30-second run, I stopped the run and measured the final voltage of the caps, to determine the input energy and then the input Power as delineated above in this thread.

Are you saying there is something wrong with this method for determining the input power?