PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[poynt99]

jmmac,

Bravo to you for demonstrating the fact that these LED's require next to no power to illuminate!

.99

[forest]

I think you know that leds produce nice amount of voltage and not so nice current when pointed directly to sun light (even if sun is not visible). At this level of current measured you have to take it into consideration even with artificial dim light around led.
I have easily got 1.4V from one clear yellow LED pointed directly to sun hidden behaind clouds in rainy day.

[JouleSeeker]

@Skywatcher, agreed.

Thank you, Stefan:

P.S: Congratulation on the new born baby Dr. Jones and family !

P.P.S: When tuning the circuit we tested today at Per-Johan´s place, I saw,
that it works like a Joule Ringer circuit.
Changing the Base current pot just changes the frequency of the
Spikes and the waveforms looks very simular to the waveforms of a
JouleRinger.

The 3rd coil on the core is the easiest way to get rid of the different DC level problems
when you want to feedback the output to the input.

Without the 3rd coil we tried to use the FWBR directly parallel at the emitter coil
and there it charged up a 2200uF to about 5 Volts, but you can´t feed this back to the input
directly cause otherwise you short out one diode of the FullWaveBrdigeRéctifier .

So the easiest part to work around this is to put a third coil around the core
and use this to extract the energy from the circuit.
Then you can also easily feed it back to the input,
cause you have no DC level problems.

Regards, Stefan.

This is NP's approach as well -- using a third coil to extract energy from the circuit, and feed it back into the input.   Hope to hear more results!

Thanks for your continued work and observations, NP! 

@Jaime -- interesting, and note that the power did not go up as you had predicted with the addition of resistor...  Of course, my goal [to be brief] is to determine whether or not a circuit involving a magnetic coil can produce Pout/Pin > 1.  There is no magnetic coil in your test, but the results regarding LED lighting are nonetheless interesting.



@all --  I heard back from Prof H, my friend with the calorimeters --

If we can put everything into the calorimeter except some wires extending to the outside and switch it on after it has thermally equilibrated, we can measure the signal and correct for the time constant of the calorimeter. It is better to have good thermal contact, but not necessary as long as we have good contact on some part of the device. The calorimeter measures thermal power, but that can be integrated to give total energy.

So it appears he is warming to my request to use his calorimeter...    At the same time, I congratulate and encourage the efforts at a self-running device! 

Thanks for the ideas regarding turning the device on and off, NP.  You see that one can have thin wires leading to the device, only to turn it on and off.  I like your idea of a gravity-switch; clever.

I'm quite sure that Prof H will allow more than one test in his sensitive calorimeter, now.
And this should be available for further tests as we learn more.  Of course, I'm hopeful that one or more of the circuits now being discussed will demonstrate OU...  that is the goal. 

Along with getting the "empowerment" out to the public in a scaled-up device!  (PS -- I do not seek the "American dream" if that dream is to get wealthy via some globalist profit-motive-control-freak corporation while humanity is screwed.  IMHO, some governments now seem focused-first on protecting  the profits of big corporations and banks.  Sometimes I wonder if the latter are not in fact in de facto control of those governments... so that government-enforcement methods are in fact applied to protect the profits of big Oil, big Banks, Monsanto, Halliburton, big Pharma, and so on. )

Prof. H states that the cavity in his calorimeter is about the size of a D-cell battery.  Please consider sending your "best" device for testing in this cavity...  and designing it to fit in this volume, and to accept power from one of two standard capacitors (which I will provide.)  One with higher C than the other; high enough so that the voltage drop will be fairly small during the course of the run... (I'm open to better ideas, as always.)

1.  Control experiment -- also to calibrate the energy in the physical capacitor =
     CapIn + R, no LED, and just let the Cap drain to a ~zero volts.  At the few-mV level, the energy left in the cap is negligible...
    E = 1/2 CV**2...  and that equation should give an energy comparable to that measured in the calorimeter CM...
   
2.  Next, we drop the DUT into the CM and let 'er run, and measure the TOTAL Poutput...

[dimbulb]

A single toroid can put out an interesting flow

http://www.youtube.com/watch?v=lMLop6MIwUU&

one person says output is linear and another sees the ring as a rotational field moving straight line.
some say both I am glad it is observable.


for example a portable radio set inside a microwave oven should not pick up a transverse wave.

the import of this post is what is observable ?

[jmmac]

@Jaime -- interesting, and note that the power did not go up as you had predicted with the addition of resistor...  Of course, my goal [to be brief] is to determine whether or not a circuit involving a magnetic coil can produce Pout/Pin > 1.  There is no magnetic coil in your test, but the results regarding LED lighting are nonetheless interesting.

Professor,

Power should go up for the same led brightness which was not what happened with my tests. Of course power will come down if i add a resistor in series with the led and do not change the rest, but the led will be less bright.

This test was only meant to show that these leds light up with very little power and so, the power inputs that we have obtained with the coil circuits don't show much by themselves.

Before i used the optocoupler (which doesn't allow me to make a coil circuit with low power input) i made 2 circuits with coils (one with a bipolar transistor and another with a mosfet) and both consumed around 1uW (should go down to 0.6uW if i remove the multimeter). The reason i introduced the optocoupler was because you suggested that the pulse generator was giving energy to the circuit, which doesn't seem the case acording to the results with the optocoupler.

I'm glad there is a good possibility of using the calorimeter, i put my money on that method

Jaime

PS: Regarding the procedure with the calorimeter, will it measure the power converted to light by the led? Using a diode would ensure all the power is converted to heat.
Can there be wires comming from the circuit to the outside of the calorimeter?