Big brain exercise! Vector based bouyancy wheel

[fritznien]

If the item on the left was in one solid piece, the replacement of water would be the same as the item on the right. Anyways, the item on the right has distributed the pressure vertically which is not the case in item to the left.

The gaps between the elements in items to the left are so close, so the water pressure are allmost equal both upwards and downwards. In the item on the right, the spacing are increased. Even if the displacements are the same, the difference in pressure on each surface is much different - or is it not?

I do not claim that I'm right, but this is how I see it anyways - probably until I understand more My only claim is that this is true, only if the bottom surface are free of pressure.

an object is buoyed up by a force equal to the weight of the fluid displaced.
this a volume thing, the orientation is not a factor.
the buoyancy force is the difference in pressure between the top and the bottom times the area.
having a differant pressure top and bottom as the object turns dose not change the buoyancy because the area changes to compensate.
fritznien

[Low-Q]

an object is buoyed up by a force equal to the weight of the fluid displaced.
this a volume thing, the orientation is not a factor.
the buoyancy force is the difference in pressure between the top and the bottom times the area.
having a differant pressure top and bottom as the object turns dose not change the buoyancy because the area changes to compensate.
fritznien

You are perfectly right. Sometimes whishes are blocking elementary math and reasonable thinking I did a quick math yesterday, and there is no bouyancy greater than the other. It ended up in zero in both cases. if there was not pressure that was applied to the very bottom of the items.
Greater bouyancy are only achieved if the volume increase, but that requires energy.

So much for the brain exercise