PLEASE READ THIS-MAJOR BREAK THRU FROM BILL MEHESS

[JouleSeeker]

@ Bolt,

GiantKiller you are 100% correct!  Any time you contract with a government dept or agency you have just given up all of your RIGHTS and converted them to restricted PRIVILEGES.   In effect  you have sold out when you contract to the government for anything. This includes so called health care and unemployment benefits or even to contract with them to hold a driving license. You need to know people the government in the US UK or almost anywhere do NOT represent the people they are corporations and are only interested in supporting their own interests as 100% commercial ventures.

Once you ask for a Patent you have just exchanged your invention and converted it to restricted contract privilege in other words you are now BEGGING to be allowed to use your invention alike a child asking for Candy! Be aware they can and often say NO to OU devices then you are totally 100% screwed as you just contracted with them by patent application and can be denied with the full force of the law under National Security.  This means they are afraid you will damage THEM the corporation as the Government of the United States has nothing to the with the people of the united states.

So you see GK is correct you become a Terrorist and so many people believe wrongly the Patriot Act is for terrorist running around in caves, setting off bombs on buses and hijacking planes but the real terrorist they are afraid is is the people of the united states becoming non compliant and thus a Terrorist by definition is one who disrupts "the system".  There is only one way.... FULL and open disclosure with nothing hidden whatsoever.

The bottom line is this you try to Patent an OU device then kiss your ass good bye it will NEVER see the light of day.

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Very Well Put Bolt.  You are exactly right.

.

Question especially for Bolt, GiantKiller and FatBird:

What if it is a Provisional Patent -- do your comments still apply?  I eagerly await your responses, taking into account what Chessnyt earlier said about Provisional Patents:

chessnyt
The patent that Bill has filed (or plans to file) is a PROVISIONAL PATENT.  It’s NOT a conventional patent and they are NOT even examined by the USPTO.  NEVER!!!  EVER!!!   Only conventional (full NON-provisional patents) are examined.  If Bill chooses to convert his provisional patent into a full patent, he has a year in which to do so.  It will be examined if he does convert it or is rejected and resubmits it.

How do I know the preceding statements are true?  Because I have filed a provisional patent and converted it before it expired for an invention that I had in the past.  If you doubt me one bit, just ask a licensed patent attorney.  I found this information out the day I retained the patent attorney who filed my application.

Chess

[billmehess]

Bill, I very much appreciate empirical results like this.  I'm fine with looking at this as a "black box" for now; and having some data to pique our interest.

My question -- as you hook up your device to a 4900mF cap (did you mean, 4900 uF?), how LONG (in seconds) does the cap take to go from 0 volts up to, say 0.5V?   From this, one can estimate the power output, which would be very instructive I think.

Yes this would certainly help me , and yes I meant to say uf not mf. When I connect the two sets of modules together in series I get again around a 700 mv out put , but the total of the summation of all the individuals is around 1400 mv, voltage loss?
Anyway at 700 mv connected to the cap. and using a multimeter and starting with the cap reading 0.00 the cap will charge at the rate of about 180 mv/hour.
Now I have a way to increase the current output substanially to radically improve the amperage available.
Based on these figures could you calculate the power output.
The physical size of the 10 modules  is around 12" x 5" x 5" total for all 10. This can be scaled down greatly but that size is not really of concern to me at this point in the game.
Bill

I just re-read above the voltage on the cap after 1 hr is 280 mv not 180 mv.

[jeffsmathers]

Hi Bill,

we are excited to see someone advance at least some in this endeavor!  Have you tried to build or cover your system with a Faraday Shield of some sort to see if there is an effect?  Perhaps you could time the rate of charge with and without the shield in place.

Good luck and good science,  Jeff Smathers  Molalla, Oregon

[JouleSeeker]

Yes this would certainly help me , and yes I meant to say uf not mf. When I connect the two sets of modules together in series I get again around a 700 mv out put , but the total of the summation of all the individuals is around 1400 mv, voltage loss?
Anyway at 700 mv connected to the cap. and using a multimeter and starting with the cap reading 0.00 the cap will charge at the rate of about 180 mv/hour.
Now I have a way to increase the current output substanially to radically improve the amperage available.
Based on these figures could you calculate the power output.
The physical size of the 10 modules  is around 12" x 5" x 5" total for all 10. This can be scaled down greatly but that size is not really of concern to me at this point in the game.
Bill

I just re-read above the voltage on the cap after 1 hr is 280 mv not 180 mv.

OK -- running, but quickly (someone pls check my math) I get:

E = 1/2 CV**2 - 0 = 1/2 * 4900 uF (0.280V)**2 = 0.192 Joules

Then, since 1 hour is 3600 seconds, the power is:

P = E/time = 0.192 J/3600 seconds = 53 microwatts

[altrez]

Can you run anything from your device without charging a cap first? For example say a Joule Thief?

Thanks!

-Altrez