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Overunity Machines Forum



Ibpointless2 Crystal Cells

Started by ibpointless2, November 02, 2011, 02:54:15 PM

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ibpointless2

Quote from: triffid on February 21, 2012, 09:38:13 PM
this is how i am calculating my watts:
volts x amps= watts
millivolts x milliamps=milliwatts


When i get 8.02 volts and .20 milliamps I do it like this 8.02volts x1000millivolts/volts x .20 milliamps=1605milliwattsx1watt/1000milliwatts=1.6watts




you have to convert volts to millivolts so you multiply by 1000.Then divide by 1000 to get watts out of milliwatts.This is how I have been doing all of my calculations.


So 1.6watts is what I am getting out of my aspirin (6)cells now.


And for the six cells of vitamin C cells,7.8 volts and .45ma   3.51watts


So both panels have dropped in their power quite a bit the second week of life.




To calculate watts for 8.02 Volts @ .20mA you must convert the .20mA to amps. .20mA = 0.0002A [size=78%]http://www.convertunits.com/from/milliamps/to/amps[/size]


Then you take 8.02 volts * 0.0002A  = 0.001604watts or 1.604mW

jbignes5



Ok Ib,


I'm starting to get the reason these guys go in circles all the time. Oxygen is the determining factor to corrosion. It is the reason they coat metals with a protective layer. It's not water it is the oxygen the water carries. Too much oxygen like in bulk water and it attacks the metals. Little to no extra oxygen like in crystalline water and the metals survive happy and very little corrosion messes up the supply of voltage and current.


Don't let them get to you, oxygen is the whole reason things corrode. Figure out how to remove the oxygen and you have the perfect transfer vehicle for current and voltage as it's guide.


The oxide might not work on the magnesium but that can be fixed by not letting oxygen touch the magnesium. The copper we can use the oxide to protect it just in case. I got to check to see if there is any previously done experiments with growing crystals in oil....

Here is a good pdf of what I am thinking about: http://www.inoe.ro/JOAM/pdf2_5/Sato.pdf

triffid

Ok PC it was IB2 getting 1.8 volts in his video.I never got it in my experiments.I saw that on his video and pretty much said WOW!
As far as calculating anything I am sorry if I was wrong in my calculations I will have to go over them.But I did report my voltages and milliamps honestly.So you can do your own calculations.triffid

triffid

Ok I guess I got my units out of whack?
volts x amps =watts
millivolts x milliamps =milliwatts.So my watts is actually milliwatts? How depressing.


It was a bad day for me today.I needed a cold beer and didnt get one.


Milliwatts is still lighting an LED however,guess I will not quit.




triffid

ibpointless2

Quote from: triffid on February 22, 2012, 05:57:33 PM
Ok I guess I got my units out of whack?
volts x amps =watts
millivolts x milliamps =milliwatts.So my watts is actually milliwatts? How depressing.


It was a bad day for me today.I needed a cold beer and didnt get one.


Milliwatts is still lighting an LED however,guess I will not quit.




triffid


don't get too down my friend, AA batteries are measured in milli-watts and milli-watts can power a LED just fine. You can do a lot with just milli-watts!  :)