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Overunity Machines Forum



another small breakthrough on our NERD technology.

Started by Rosemary Ainslie, November 08, 2011, 09:15:50 PM

Previous topic - Next topic

0 Members and 26 Guests are viewing this topic.

poynt99

Quote from: Rosemary Ainslie on March 15, 2012, 05:28:12 PM
Here's where you claim that the current is from the battery - Poynty Point.There is NO current flow from that SOURCE.  Unless you mean something entirely different by the use of the word 'source'?

Rosie Pose
ADDED - FOR EMPHASIS

Strictly speaking, I should have said  "the voltage difference across, and the current through" the element.

Just because the battery is connected doesn't mean the current has to be coming from it; it can also be going to it.
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

Rosemary Ainslie

Guys,

It's rather disheartening to argue a condition through pages and pages of thread discussion - only to find oneself back at the starting line.  The kick off argument. We've got an oscillation that is PERFECTLY in phase as shown in Poynty's oscillations and our own waveform downloads.  I'll post a sample of this when I've done here. The battery and the voltage and the current flow through that battery - in either direction - are perfectly 'in phase'.  They're in lock step.  Not a shadow of a variation from 'true'.  If they were 'out of phase' then that oscillation would degrade in no time at all.  It simply DOES NOT DEGRADE.

Now.  What I know - very, VERY well - is that Poynty is also really, really bright.  So when he posts something like this..
Quote from: poynt99 on March 15, 2012, 05:20:08 PMPhase shift is evident in all parts of this circuit
and this...
Quote from: poynt99 on March 15, 2012, 05:20:08 PMThere is inductance and capacitance, and a high frequency oscillation. In fact if it weren't for a significant degree of phase shift, the circuit wouldn't oscillate at all.
then I need to know why he states something so profoundly erroneous.  As this diametrically opposes the evidence.  And he is too bright to not know this.

Gravely confused.  Hopefully he'll explain himself.
Kindest regards,
Rosemary

 

fuzzytomcat

Quote from: Rosemary Ainslie on March 15, 2012, 06:00:00 PM
Guys,

It's rather disheartening to argue a condition through pages and pages of thread discussion - only to find oneself back at the starting line.  The kick off argument. We've got an oscillation that is PERFECTLY in phase as shown in Poynty's oscillations and our own waveform downloads.  I'll post a sample of this when I've done here. The battery and the voltage and the current flow through that battery - in either direction - are perfectly 'in phase'.  They're in lock step.  Not a shadow of a variation from 'true'.  If they were 'out of phase' then that oscillation would degrade in no time at all.  It simply DOES NOT DEGRADE.

Now.  What I know - very, VERY well - is that Poynty is also really, really bright.  So when he posts something like this..and this...then I need to know why he states something so profoundly erroneous.  As this diametrically opposes the evidence.  And he is too bright to not know this.

Gravely confused.  Hopefully he'll explain himself.
Kindest regards,
Rosemary



I wonder exactly which electronic schematic went with the "SCOPE SCREEN SHOT" dated 2-11-2011 ........... "Prior" to the world renowned COP>INFINITY demonstration ??

8)

added - http://www.overunity.com/11675/another-small-breakthrough-on-our-nerd-technology/dlattach/attach/96507/   ( another P'rat example.png )

fuzzytomcat


Rosemary Ainslie

I'm trying this again Poynty
Quote from: poynt99 on March 15, 2012, 05:37:07 PM
Strictly speaking, I should have said  "the voltage difference across, and the current through" the element.
If the phase shift only applies to to the current through and the voltage across the element resistor - then that will be measured as the heat dissipated over that resistor.  The greater the phase shift the less the heat dissipated.  Now.  What has that to do with the oscillation?  The current flow below zero can be explained as the energy being returned TO the battery.  The current flow greater than zero can be explained as the energy delivered BY the battery.  We're only trying to determine the amount of energy that is delivered by the battery. But the problem is that current delivered BY the battery is from where?  Because the battery is disconnected.  Do you see the problem yet Poynty Point?  There is no reasonable explanation for the source of the potential difference that is responsible for each positive half of each of those oscillations.   

And PLEASE do not advise all and sundry that the oscillations are due to phase shifts.  That perpetuating oscillation is enabled PRECISELY because there ARE NO PHASE SHIFTS.  You surely know this?  If there were phase shifts happening across that battery then there would be no oscillation.  Or it would be very 'brief' at best.

Quote from: poynt99 on March 15, 2012, 05:37:07 PMJust because the battery is connected doesn't mean the current has to be coming from it; it can also be going to it.
We know that the current can be returned to the battery.  We don't know how the it can be coming FROM it.  Unless it's from CEMF.  BUT.  If it's from CEMF then that second half of each oscillation is actually REGENERATED from the material of the resistor element and from the inductance on the circuit components.  It simply CANNOT be coming from the battery supply.  Which means what?  Does this then indicate that CEMF is not so much 'stored' as 'regenerated'.  In which case?  That also means that - quite possibly - over unity is actually a REQUIREMENT in terms of inductive laws.  And then, possibly, this eccentric Q-array is simply exposing the second half of CEMF that is usually resisted under normal switching configurations?  I suspect so.  I think that potential has always been there but has never been fully explored.

Kindest regards,
Rosemary
added