another small breakthrough on our NERD technology.

[Rosemary Ainslie]

Golly Guys,

it seems our tickytacky TK feels insulted?  That's not right.  If I were you TK I'd write a letter to Harti.  Again.

And... by the way, insulting dolt idiot Ains-lie: I am 72 inches tall,

You WISH 

and since there are 12 INCHES PER FOOT, that makes me a bit taller than you, ...

If you want this believed you need to stay out of your video shots.  My best guess is 5ft 6" - barefoot.  And I'm all of 5ft 9" plus a tad.

But just what do my height and moustache have to do with anything? Nothing at all...

It has considerably more to do with this thread than your absurd posturing and your equally absurd claims. And this entirely inappropriate ownership assumption of my thread.

just like you being a feeble and ugly  old woman doesn't have anything to do with your LIES and MISREPRESENTATIONS.

Indeed.  I am both ugly and old.  And FEEBLE.  LOL

Rosie Pose

[Rosemary Ainslie]

Rosemary,

I know where the 50 Ohms comes from, but where does that extra 1000 Ohms reside? Did you see the diagram I posted in REPLY #1475?

Poynty - if the current is going through the terminal probe to terminal ground (as MileHigh explains this is termed) then it has to move through 1000 Ohms of secondary inductor wiring that lies between those those two terminals. 

Regards,
Rosie

[TinselKoala]

TK,

My detailed analysis of the actual build from the video demonstration and my discovery of the connection error I made many many months ago still stands. If you wish, you may go and read all that. It's been fairly well covered.

.99

I know I reviewed it at the time. But could you refresh my memory, please? On which side of the shunt resistor is the FG's "negative" lead to be connected? I have work here in progress, you know.
I don't think in practical terms it matters much since the shunt in her circuit is 5 resistors connected in parallel to make a value of ... what now? Stated to be 0.25 ohms? From 5 in parallel? What are the values of the individual resistors I wonder. Perhaps they are actually 1 ohm resistors..... but I doubt if they are 1.25 Ohm resistors.
Whatever, 0.20 or 0.25 or, in my circuit, 0.33 Ohms isn't going to make much difference... except when the FG shorts out the CVR.

But... your post caused me to go back to the beginning of this thread.... where Rosemary tells us that three of her batteries... well, here are her own words:

And there's more good news.  You guys have all called for us to run our batteries to the duration.  That experiment would have taken too long and the test itself too expensive to monitor.

However.  The guys have gone about this differently.  They flattened 3 of our batteries by running lights off them.  When the lights 'went out' was when the batteries were considered flat which was at 10.05 volts or thereby.  Immediately thereafter they ran our resistor element on our usual test.  Not only did we get the same level of oscillation but precisely the same level of heat dissipated - related to that oscillation.  Which was proof that the energy in that oscillation is indeed NOT coming from the battery supply.

Yet she says now that her batteries have never been below the fully charged level.

And by the way, Rosemary... I can PROVE that I am seventy two inches tall, and I dare say that you have NEVER seen me at full height in any of my videos. Again, you are making a fool of yourself by talking shite about things you know nothing about.

[poynt99]

... through 1000 Ohms of secondary inductor wiring that lies between those those two terminals. 

Rosemary,

Please explain what you mean by "secondary inductor wiring", and "those two terminals". The two terminals of the FG probe? Sorry, I don't understand what you mean by the above.

[poynt99]

TK,

Maybe this will help.

.99