SMOT

[felix]

Rollaround is illusion
I have investigated a long time the SMOT and came to the final conclusion,
that a real rollaraound is illusion.
Maybe you may get one or two rounds, but this is due to the initial
energy you gave to the ball when placing it at the start location.
It is like a spring that you load. This gives the ball an inititial impulse
which lasts for a moment, if you are very, very lucky one or two
rollaraounds. But then the game is over ...
J.L.Naudin calculates an OVERUNITY for the SMOT.
This is nonsense, because he does not include the energy
which he needs initially to "load the spring".
If you use an ordinary spring, load it, and measue then the
jump of the ball, you will get the same result.

Sorry I have to communicate you this result.

Keep working on other projects, my best candiadte is Testatika!

Regards
            Felix

[Sojourner]

Did I just see what i think I just saw? Isn't this overunity?

Soj

Hi Greg,
this GIF is too big,
I am attaching to this message an AVI file which In converted to 1 frame/sec
which is only about 400 Kbytes big !
Regards, Stefan.

[prometheus_effect]

here is something kind of like it.
http://www.diac.com/~ekwall2/ffsmot

Hi Steve,

The very big problem here is the ball rolling track losses will be really large due to the inner track being of a tighter radius than the outer track. The ball will skid along one track and lose a lot of energy. Have a look at the SRRS design in the files section of the Prometheus Effect group web site for a better solution.

http://groups.yahoo.com/group/prometheus_effect/

Greg

[prometheus_effect]

Rollaround is illusion
I have investigated a long time the SMOT and came to the final conclusion,
that a real rollaraound is illusion.
Maybe you may get one or two rounds, but this is due to the initial
energy you gave to the ball when placing it at the start location.
It is like a spring that you load. This gives the ball an inititial impulse
which lasts for a moment, if you are very, very lucky one or two
rollaraounds. But then the game is over ...
J.L.Naudin calculates an OVERUNITY for the SMOT.
This is nonsense, because he does not include the energy
which he needs initially to "load the spring".
If you use an ordinary spring, load it, and measue then the
jump of the ball, you will get the same result.

Sorry I have to communicate you this result.

Keep working on other projects, my best candiadte is Testatika!

Regards
? ? ? ? ? ? Felix

Hi Felix,

There is no spring effect here. The ball is drawn into the entry of the SMOT. Have a look at the slow motion videos on the Prometheus Effect site.

Greg

[prometheus_effect]

Hi Greg,
this GIF is too big,
I am attaching to this message an AVI file which In converted to 1 frame/sec
which is only about 400 Kbytes big !
Regards, Stefan.

Thanks Stefan.

Greg