Ghazanfar Ali Generator - Utlilizing trapped energy

[Ghazanfar_Ali]

@Qwert
Many thanks for spending your precious time in compiling my previous posts.
Best Regards
Ghazanfar Ali

[Groundloop]

Ghazanfar_Ali,

I have started to build this circuit. Got the Ferrite coil and heat sink for the mosfets mounted already.
Next step is finding some mosfets and solder the circuit together.

One question for you, you say that if the load is low then the electrolytic capacitor will charge.
My question is, if I connect the circuit to a 12 volt lead acid battery, then will the battery charge
with no load on the circuit?

Groundloop.

[poynt99]

@poynt99
As far as 800W output sim file is concerned, dont waste your time on that. It is unstable schematic. Damping occurred after 4 minutes in my case. However schematic of 42 W output is stable. I made it the hardware run for 1 and a half day and the bulb was continuously lighting.

Ali,

I had already switched to the 42W version (i.e. 150 Ohm load), but the oscillation only holds at 200V for about 20ms, then starts falling off. I've tried 150k Ohms for the R1 load and still the oscillation eventually falls off.

We need your working ORCAD files here Ali.

.99

[mscoffman]

 @Ghazanfar_Ali
I think you should try driving the signal generator into
the led of an opto-isolator, then using a 6VDC battery
to generate the pulses out from the opto-isolator. The reason
is that the output of the signal generator will have some
capacitance to the utility line determined by the generator
itself with potentially high hum voltages. You really have to
isolate the signal generator lines from ground with a low pass
filter. This is why they often have a circuit link on back the instrument
to separate the chassis ground from the signal ground on high
quality instruments. But opening that link will not necessarily solve
this problem.


If the pulse are shaped the same you would need to ask
your self why can’t the battery do what the signal generator
did?

You always should isolate a signal generator from ground
before using it’s output where isolation maybe critical.

:S:MarkSCoffman

[Ghazanfar_Ali]

@Groundloop
No the 12 V Bty will not be charged if you connect it instead of C2. The minimum driving voltage for the device must not be less than 24 V as an initial charge in C2 whether 150 Ohms load is connected or not. I did not test this situation but my hypothesis says that i may not work in case of 12 V Bty. But u can try.