Is joule thief circuit gets overunity?

[poynt99]

Lawrence.

You should try shorting your current scope probe to itself and see what the average voltage is that it reads. One would expect 0mV correct?

Let us know the result of this simple test.

[NickZ]

  All I see is the capacitor discharging, just like the pile of dead batteries that you are not mentioning, to confuse us further.  I'm not convinced, even though I believe that it is possible, but not from your low efficiency circuits.
Stefan has also had more than enough time to let us all know just how long it took to discharge the new AA that he is using on his test circuits that you sent him.
   I think that I know why...

[ltseung888]

Lawrence.

You should try shorting your current scope probe to itself and see what the average voltage is that it reads. One would expect 0mV correct?

Let us know the result of this simple test.

@poynt99,
Correct.  Shorting the probes produced 0mV.   When will you show us your results?

[ltseung888]

  All I see is the capacitor discharging, just like the pile of dead batteries that you are not mentioning, to confuse us further.  I'm not convinced, even though I believe that it is possible, but not from your low efficiency circuits.
Stefan has also had more than enough time to let us all know just how long it took to discharge the new AA that he is using on his test circuits that you sent him.
   I think that I know why...

@NickZ

The main point of the video is that the Average Input Current reading changed from -14mV to +2mV with dropping voltage.

The Input Voltage, the Output Voltage and the Output Current are all positive all the time.  The Average Output Power -computed from the average of (Vout x Iout) sample points is always positive and the absolute value is well above that of the Average Input Power.

The Average Input Power can have very low values especially near Iin (CH2 Vavg) = 0.0mV.  This will give rise to relatively large COP (both negative and positive) values.

Please watch the video again and focus on the Iin (CH2 Vavg) display during the seven minutes.  This result can be produced even with a single channel analog Oscilloscope.  TK has his own board and his Scope.  I am not too sure what Stefan has but the above youtube experiment can be repeated with ease.  Just use a capacitor if the tester does not have a DC Power Supply.  That will save the trouble of finding depleted AA batteries with different remaining voltage values.

The best results will be from poynt99 with his 4-CH DSO and his DC Power Supply.

[NickZ]

  You are blind, or what?  No need to answer me, I know that you are more than just blind.
The capacitor is dead, no matter what the readings are showing. Can't you see this???
  There is not a single Joule Thief that you have shown or talked about in the last several years that has anything going for it. Not one. They all are just simple oscillators using up all the available CURRENT provided by the battery. Open your eyes...
  You are not convincing me with your two oscillator readings, and PILE of dead batteries, that you won't talk about. Right!
  What in Gods name are you raving about!!!