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Overunity Machines Forum



Kapanadze Cousin - DALLY FREE ENERGY

Started by 27Bubba, September 18, 2012, 02:17:22 PM

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0 Members and 717 Guests are viewing this topic.


willz

According to this inventor , the free energy that he is generating is from " Muons".

Summary: The voltage output from the muonic generator follows a function of 4 variables:
V=F(f, D, N, L);
where f is the frequency of the oscillator, D is the diameter of the coil, N is the number of turns of the coil and L is the length of the coil.

So according to him the frq of tesla coil should be tune to muons wavelength =======" λB=n×λC=n×5.88×10−23 m"

A commercial battery of 9 V and 0,1 A (therefore, of 0.9 W), which was connected to a device as in FIG. 1 with an outer coil 7 with a length of 25 cm and with a copper wire of 3 mm and a radius of 5 cm. The inner coil was also made of copper, with a wire of 5 mm and a radius of approximately 4 cm. A "chip" or integrated circuit PIC (32) ("Programmable Integrated Circuit") is programmed to oscillate at wavelength λB above mentioned within the oscillator 4. Only as an example, one can use a Hartley type oscillator. The "PIC" 32 already pre-programmed to emit the λB above defined is inserted as in FIG. 5. The load utilized in this experiment consisted of 15 110 V 60 W bulbs, therefore a total charge of 900 W. Highly surprisingly, all the bulbs lit up with irradiance and normal brightness to the naked eye.
This resulted in a COP of 1000, thanks to the capture of atmospheric muons.

As indicated above, it is an essential characteristic of the present invention that the oscillator 4 is tuned to the frequency of the wave function to capture the energy created by the decay of muons in the centre of the core 12 in relation to the above equation λB=n×λC=n×5.88×10−23 m. Empirically it was established that λB should be around 5,88324456243×10−23 m. This wavelength is obtained with great precision by way of a "chip" or integrated circuit PIC ("Programmable Integrated Circuit"), which is programmed to oscillate at exactly this wavelength. The programming of the integrated circuit is done by way of a PIC commercial programmer.

willz

https://www.youtube.com/channel/UCmsg5LpGICV-jgJ2P1UirMg         ,Ruslan  had some comments ...                                                             

willz

Currently, the only reasonable solution, without tesla hocus pocus witchcraft...

NoBull

Quote from: willz on October 30, 2016, 09:27:07 AM
Empirically it was established that λB should be around 5,88324456243×10−23 m. This wavelength is obtained with great precision by way of a "chip" or integrated circuit PIC ("Programmable Integrated Circuit"), which is programmed to oscillate at exactly this wavelength.

Bullshit with a cherry on top!

588 zeptometers is shorter than the wavelength of Gamma rays and smaller than the atoms from which a PIC chip is made out of.

BTW: Muons do not occur naturally on Earth. They are produced in the sky by cosmic rays.  Only ~10000 Muons reach every square meter of the Earth's surface a minute.  Each Muon has the same charge as an electron, so one can expect only 167eV/s from them on Earth's surface.  That's a laughable power.  A flying mosquito has the power of 1TeV/s.
Also, muons are unstable.  They have a half life of only 2.2us.

No Bull