Kapanadze Cousin - DALLY FREE ENERGY

[AlienGrey]

Hoppy,

yes, that could be, therefor any input from him would be appreciated.


Void,

yeah, if you include the TL494 and IR2113 power, like it should.
Its also like you mentioned, with feedback the input goes up big time.

Itsu

If you look at Smith's device now they all use a neon zener efect regulator but the problem is it doesn't bottom rail
Tesla used magnet quenched spark gap if you want the same effect your talking charged carrier rise time 10-9 or your wasting your time.

[AlienGrey]

If i could get access with an AI computer and give it this crop circle
i can guaranty that it will come up with a free energy circuit.

Look at the links between the circles THEY SCREW UP there    ask em to show you the ropes next time

[Belfior]

If i could get access with an AI computer and give it this crop circle
i can guaranty that it will come up with a free energy circuit.

Isn't that a magnifying transmitter in the picture? Showing how the energy is amplified?

[Void]

Can negative voltage be thought of like energy coming at me? That is what it means to me anyway. So can I take the backEMF from a coil and redirect that back into battery?
What if I charge a cap with an NST that lets only negative wave into the cap? So I am pulling from the cap plate. Then on the other side I have load and ground. Will the ground supply the other plate?

Hi Belfior. Often when people use the term 'BEMF'  or 'back EMF' in relation to a coil, they really mean the
'flyback' spike on a coil that occurs when you cut off the current flowing in a coil quite sharply and the magnetic
field around the coil collapses and induces a voltage spike in the coil. The energy that gets stored in the magnetic field
around a coil comes from your power source (battery, power supply, etc.) It is not extra energy from outside the system.

I have tried connecting one plate of a HV capacitor to a DC high voltage which is battery powered and isolated from ground
with the other capacitor plate connected to ground, but only saw a tiny charging effect on the capacitor. It takes a flow of
current from one plate of a capacitor to the other plate to charge a capacitor. You are 'pulling' charge from one plate and packing
it into the other plate. This movement of charge from one plate to the other is a current.  That charge displacement takes an expenditure
of energy to do. I have tried placing a HV diode across the plates of the HV capacitor (in both directions) in this configuration to try to
facilitate that current flow between the plates, but still could not get much charge on the capacitor.  I could not get that approach to work.

[Belfior]

Well Faraday and Maxwell say it is the rate of change, that dictates the current on the other side. The displacement current. Try with 4-9kV sharp DC pulses. I would also say very high frequency. I think high rate of change means a sharp drop and how many drops per second.