Kapanadze Cousin - DALLY FREE ENERGY

[gyulasun]

Hi magpwr,

IT is okay that you have not worked with TL494 circuit, so let me help that it has two open emitter outputs, Pins 9 and 10, so the two 100 Ohm resistors are the ground return path for the two open emitters, if you remove them, the two output bipolar transistors of the TL494 cannot work properly.  (Data sheet is here:  http://www.ti.com/lit/ds/symlink/tl494.pdf  )

One more thing with the resistors: it is always good when the input pins of a MOSFET driver IC see a low impedance to the ground (like the 100 Ohms represent) because in case those input pins are left with a relatively high input impedance i.e. no any termination other than a (possible higher) impedance of previous driving stage, then the inputs may pick up stray EM fields from the big output coils that can cause erronous drive signals to get through to the gates of the MOSFETs, you would not want it happen.

One more thing on the role of diode VD4 (you suggest to remove), I am not sure it would destroy both the 7414 and 7400 ICs. 
Watch diode VD1, I think it brings pulses from the output of one of the MOSFET driver ICs and notice resistors R1 (250 Ohm) and R10 (1 kOhm) form a voltage divider: these surely limit the voltage and current what diode VD4 can forward to the 5V rail what the 7805 (shown above it) insures when the 12V is present. Notice that this 12V comes from a time relay switch so I suspect that during self looping the 12V supply voltage to the input of the 7805 is OFF and the 5V to the 7414 and 7400 comes via just diode VD4, no? 

Gyula

...
Lastly the both inputs of UCC Driver at pin 2 was technically shorted to the ground using 100ohms resistors .Both 100 resistors to be removed.

Unverified and untested area in circuit portion.
{
Since i have ever worked with TL494 for PWM generator.I am unable to advise at this moment if there is any issue at this area.
PWM generator issue  base on TL494 can be easily solved by referring to other circuits.
Only pending items is the snubber components which can be fixed through experiment.
}

....

[magpwr]

Hi magpwr,

IT is okay that you have not worked with TL494 circuit, so let me help that it has two open emitter outputs, Pins 9 and 10, so the two 100 Ohm resistors are the ground return path for the two open emitters, if you remove them, the two output bipolar transistors of the TL494 cannot work properly.  (Data sheet is here:  http://www.ti.com/lit/ds/symlink/tl494.pdf  )

One more thing with the resistors: it is always good when the input pins of a MOSFET driver IC see a low impedance to the ground (like the 100 Ohms represent) because in case those input pins are left with a relatively high input impedance i.e. no any termination other than a (possible higher) impedance of previous driving stage, then the inputs may pick up stray EM fields from the big output coils that can cause erronous drive signals to get through to the gates of the MOSFETs, you would not want it happen.

One more thing on the role of diode VD4 (you suggest to remove), I am not sure it would destroy both the 7414 and 7400 ICs. 
Watch diode VD1, I think it brings pulses from the output of one of the MOSFET driver ICs and notice resistors R1 (250 Ohm) and R10 (1 kOhm) form a voltage divider: these surely limit the voltage and current what diode VD4 can forward to the 5V rail what the 7805 (shown above it) insures when the 12V is present. Notice that this 12V comes from a time relay switch so I suspect that during self looping the 12V supply voltage to the input of the 7805 is OFF and the 5V to the 7414 and 7400 comes via just diode VD4, no? 

Gyula

hi Gyula,

I am aware the spec for TL494 and pwm ic i use SG3525 is about the same with the exception for different pin layout that's all.

There is no need to short 100ohms to ground at all.Pin 2 of Igbt driver can be connected directly to tl494.

The connection to nanosecond generator section should be connected directly from pwm generator.For me the signal diode to positive supply is not required.

Lastly if anyone notice there is 2 function nanogenerator section is providing.

1)Once the irf4905 is switched on it provide positive bias for the
2sc2500 transistor which the base is connected to tesla coil.Basically these transistor would resonate at the specific frequency of the pre-tuned tesla coil.

2)nanosecond generator is in sync with frequency around 27khz.
Think about it tesla coil is already running at it's pre-defined frequency and nanosecond pulse in kv would be present in the waveform of tesla coil.

Looks like there 3 signal around 27khz,tesla coil freq,nanosecond pulse provided for this device.

[NickZ]

  Geo:
  Let me see if I understand...
   Is the power supply unit in the Ruslan's diagram the same as the inverter shown in the videos?  Does it take the AC output at the bulbs, on the output air coil. 
And is this AC output then connected to the inverter (what is normally the inverter's ac output side???), which is then backward rectified to 12v by the inverter, and is sent back to the device input side, as a 12dc input,  to self run.
  Is this what is happening, or do I have it all backwards?

[Void]

  Let me see if I understand...
   Is the power supply unit in the Ruslan's diagram the same as the inverter shown in the videos?  Does it take the AC output at the bulbs, on the output air coil. 
And is this AC output then connected to the inverter (what is normally the inverter's ac output side???), which is then backward rectified to 12v by the inverter, and is sent back to the device input side, as a 12dc input,  to self run.
  Is this what is happening, or do I have it all backwards?

Hi Nick. Typically when people use the term 'inverter', they mean a circuit that converts
from DC to AC, for example from 12VDC to 120VAC (or to 220VAC). This is because a typical power supply
usually converts from AC to DC, for example from 120VAC or 220VAC to 12 VDC or 24 VDC, etc., so an
'inverter' would be the opposite. If your output of your circuit to your load is say 220VAC, then you would use a power supply
that can convert from 220VAC back to whatever DC voltage you need to run your driver circuits. For example, to 12VDC or 24VDC.

From what I see in Ruslan's recent hand drawn schematic, he is actually showing converting the output from the bifilar coil to DC
first using diodes and large filter capacitors, and powering the light bulbs using this resulting 220VDC. Not sure why he is doing that,
but maybe because full wave rectifying will increase the voltage to near the peak output AC voltage (if sinusoidal).
According to that schematic,  he is using this rectified and filtered output voltage (220VDC) to go to his lights and then on to his power supply,
which can apparently take 220VDC at its input and convert it down to the 12VDC output, which is powering his circuits (inverter driver and kacher driver circuits).
If it is a switching power supply, it may work fine with either 120/220 volts AC or DC at its input. Depends on the power supply.

Here is a rough drawing to show how the output power would typically be looped back through a
suitable power supply, back to power the driver circuits. There are of course other possibilities.
It depends on what you want/need.
All the best...

[Jeg]

From what I see in Ruslan's recent hand drawn schematic, he is actually showing converting the output from the bifilar coil to DC
first using diodes and large filter capacitors, and powering the light bulbs using this resulting 220VDC. Not sure why he is doing that

We have already covered this but it is a long time ago. These diodes and caps that you are referring about make demodulation of the mixed signal. (See am demodulation with diode and cap...).

What I would like to ask is if this 220v ac to 12v dc converter is able to handle a higher frequency than 50Hz at the input, cause its input frequency is at KHz range.