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Overunity Machines Forum



The Paradox Engine

Started by Tusk, November 16, 2012, 08:20:52 AM

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gravityblock

It appears the force of the secondary reaction is the result of utilizing the portion of the kinetic energy of the object during the time period when the circular motion is in the reverse direction of the linear motion as a result of it's spin energy (see snapshot below for better clarification).  This means that 100% of the effective mass will be utilized, instead of only half of the effective mass, thus we can drop the ½ in our kinetic energy equation, for it doesn't apply in this particular case!  I think this is in-line with what Tusk has been describing and with what the data is showing, which is E = mv2 in regards to this concept, while providing a solution to this paradox by using simple mechanics!  I would love to hear your thoughts!

Gravock
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

Tusk

It's a slightly uncomfortable fit Gravock but certainly under acceleration/deceleration the receding side of the disk still 'pulls it weight' in terms of inertia (or inertial resistance if you prefer) from the point of view of the EM drive unit; and in so doing creates an inertial lever action at the disk cm/axis which I have named the 'secondary reaction'. So in that respect yes, there is a manifest advantage due to the reverse direction of half the disk.

With the disk axis secured this reaction has little or no part to play, but by allowing movement of the disk axis (circular as with the PE apparatus although a linear motion is also possible, since the secondary reaction is linear and parallel to the applied force) our only real problem is keeping up with the advancing disk as it accelerates away from our point of applied force. I went some way towards solving this issue with geometry and an EM drive unit but alas, the apparatus looks like a trick of simple torque effects to all but the most perceptive eyes.

It might have been preferable to have the disk on a carriage mounted on a magnetic rail drive, thus removing torque as an issue. Actually for clarity the disk should be mass biased to it's outer circumference, so then a ring mass, which has the same (or similar) inertial mass in both linear and rotational motion. In such a configuration I am quite confident that the rotating disk (ring mass) would arrive at the limit of travel of the rail with more energy than a non-rotating disk, and for no additional input; since the secondary reaction must accelerate the rotating disk equally to the non-rotating (axis secured) disk, yet the axis free disk must rotate.     




CANGAS

Quote from: gravityblock on September 09, 2014, 07:03:19 AM
This isn't a scientific or mathematical rebuttal to what I posted.  Please post your rebuttal so we may start the debate in which you do not want to start.

Gravock


QuoteThis isn't a scientific or mathematical rebuttal

LOL! You don't miss a clue, Sherlock. Your guess is correct. My post was actually a simple QUESTION. And you have evaded it, but have have amply answered it by implication.

It looks like you don't have a clue where the v "SQUARED" came from in the Newton physics Kinetic Energy Equation, or, the "1/2" in the same equation. Which therefore explains why you don't have a clue why Einstein left out the "1/2" in his famous Energy Equation.   



CANGAS 69

gravityblock

Quote from: CANGAS on September 10, 2014, 03:14:02 AM

LOL! You don't miss a clue, Sherlock. Your guess is correct. My post was actually a simple QUESTION. And you have evaded it, but have have amply answered it by implication.

It looks like you don't have a clue where the v "SQUARED" came from in the Newton physics Kinetic Energy Equation, or, the "1/2" in the same equation. Which therefore explains why you don't have a clue why Einstein left out the "1/2" in his famous Energy Equation.   



CANGAS 69

The question was answered prior to you asking it, and can be found in the reference links of the papers I have already provided.  Maybe you should read those papers and learn something!

Gravock
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

Tusk

Gentlemen, please; may I suggest pistols at dawn...... spring powered ball bearing type I think, with the following specifications:

Pistol A: 1kg force spring (at max compression) effective force 500g over 10cm (from full compression) loaded with 1 x 50g shot

Pistol B: The same type spring loaded with 1 x 200g shot

No paces, just turn and shoot, point blank range; choose your weapon....... no perhaps not. How about points for best range and most damage (dummy target) ? We might all learn something useful.