Free Solid State/mechanical energy

[allcanadian]

I know I have posted alot of stuff here, the point I would like everyone to keep in mind is that Im not the teacher here, erfinder is, Im the student. I read what is given, a direction I follow to succeed in understanding. What I post is my interpretation of what I have read- nothing more, I could be completely wrong and that is part of my means to succeed, the understanding that everything I believe may be wrong.
So I put my thoughts out there for you to criticize so we can all succeed.

[samebarbosi]

Well as I said I have more than one question and all because we (or at least me) made a series of assumptions.
I don't mean I'm asking for straight answers, but rather I try to mark the unexplored areas where the conventional science filled the gap. So we made the assumptions.

As a start, one question is what is an electrostatic charge and how is getting charged? Even the answer with rubbing the ebony stick, blah, blah, that rubbing has the mechanical "rubbing valve" involved.

Later we assumed the step up transformer model and I realize I don't know how that charge gets multiplied.

And that is just the start.
I hope you get the message of my doubt.

Cheers.

[allcanadian]

@samebarbosi

Later we assumed the step up transformer model and I realize I don't know how that charge gets multiplied.

Your not the only one, I completely ignored the fact that every transformer section raises the voltage above the last section in series. So the maximum voltage in this machine could be massive, which is needed I think.
I think Im ready for some tinkering, Im going to build erfinders machine with no armature or rotor, out of some stripped transformers so I can get a hands on understanding as I go. Understand one part of this machine at a time, hopefully.
Don

[samebarbosi]

For an answer to how a charge gets amplified in secondary, I think the answer is: "it doesn't get amplified".

Simply the vacuum created around the primary, is filled with charge. From where? don't know - void? Anyway, the bigger the capacitance of a coil, the bigger the charge, the higher the potential.

But this is just a guess. I'm going over 569176 and 593138 to seek answers.

As for what a charge is, I think this is going to be for later.

[Maximumgravity1]

"It is well known that the higher the frequency or potential difference of the current the smaller the capacity required to counteract the self-induction;"

Higher frequency implies a faster rate of change - not a higher potential.

This makes it even more confusing - why does a faster rate of change (frequency) need less capacitance (stored energy) to over come self-inductance?

I guess this is in-part the answer:
Self-inductance: The property of an electric circuit or component that caused an emf to be generated in it as a result of a change in the current flowing through the circuit.

Positive Charge = Paramagnetism = EMF
Positive charge attracts positive charge, and expells negative discharge.

So since positive charge attracts itself, and expels negative discharge, if the differences between the potentials are elevated, and the frequency (rate of change) is also increased, the faster the current changes, the more emf (pressure, force) is produced, as well as BEMF (negative, repulsion). 

So is this also stating that a higher frequency causes a coil to act as its own capacitor? Could we get a high enough frequency to remove all self-inductance?  What would this do for us?  IT seems apparent that two coils could remove the need for a capacitor, as each would be removing the others self-inductance (assuming a high enough frequency). 

Now I have to think on this, I lost my original thought....