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Overunity Machines Forum



Big try at gravity wheel

Started by nfeijo, May 03, 2013, 10:03:04 AM

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0 Members and 56 Guests are viewing this topic.

Marsing


yes it's still below unity, i think there is no much difference from your drawing,
i read about plc/controller somewhere in the zed thread, and in my opinion they used valve.
so i draw them.

the unresolved problem is still "third energy"( compressor, controller),

lol

MarkE

Marsing a solution for the lost energy might turn up with Orson Welle's "The Third Man".

MarkE

Quote from: webby1 on February 17, 2014, 01:40:39 PM
Marsing,

Lets go ahead and cycle the transfer pump.

The pump is moved from one side over to the other and fills the cylinder with air, in my testbed I was using an open chamber cylinder so it was a full air charge needed, this brings the cylinder into a buoyant lift condition and will lift the weight on top of it, things move up and at the predetermined height the cylinder is held firm, the weight is removed and its potential is applied to a mechanical linkage that drives the transfer pump.

At this point you can see that the transfer pump has 2 input sources and 1 output.  Those are, the weight and mechanical linkage and the other is the pressure inside the cylinder.

Since both of these inputs can be viewed as inputs, we can choose how they are applied.
Webby do you not understand that energy efficiency is the ratio of delivered energy to applied energy?  You claim ~83% energy efficiency.  That is not something that you can even remotely approach with what you have documented.  With the dimensions you have stipulated, your output work is: 26.5g * 15mm = 3.98mJ.  Show that you input no more than ~4.8mJ to get there.  Please show that your 83% energy efficiency claim has any merit at all.

Marsing

Quote from: webby1 on February 17, 2014, 01:40:39 PM
Marsing,

Lets go ahead and cycle the transfer pump.

The pump is moved from one side over to the other and fills the cylinder with air, in my testbed I was using an open chamber cylinder so it was a full air charge needed, this brings the cylinder into a buoyant lift condition and will lift the weight on top of it, things move up and at the predetermined height the cylinder is held firm, the weight is removed and its potential is applied to a mechanical linkage that drives the transfer pump.

At this point you can see that the transfer pump has 2 input sources and 1 output.  Those are, the weight and mechanical linkage and the other is the pressure inside the cylinder.

Since both of these inputs can be viewed as inputs, we can choose how they are applied.

webby,

ok, transfer pump has 2 input,

can you supply a drawing/sketch how to move weight and its potential is applied to a mechanical linkage that drives the transfer pump ?.

MarkE

Quote from: webby1 on February 18, 2014, 01:50:39 PM
Marsing,

A simple method could be to have the weight as a large steel ball resting on a small track on top of the cylinder, when it reaches the top of the lift that ball is released and rolls over and onto a waiting platform that is held up by a string, that string goes over a pulley and down and runs a cam drive gear that runs the pump.  These are designed so that at the end of motion the ball and the cylinder are back down at the same height where the ball can roll back onto the cylinder.

With proper design, and if symmetry and CoE are valid considerations, then you can see that this system, baring frictional losses, can readily hit 100 percent efficiency.
First, you would have to show that you do not have energy losses.  You can assume a frictionless, leak free pump and you don't get there.  You can add a big energy intermediate, nearly isobaric energy store and you don't get there.  Yet, you keep saying that you have already gotten 83%. 

What did you actually do to try and determine the efficiency of your device when you came up with that 83% value?