New Perm Mag Engine Design 1.5 : 1 Ratio (work from magnets)

[Floor]

@conradelektro

Previous post was also @conradelektro

I don't want to make any claims at this time, and I do not want anyone else making claims at this time, at least not here in this topic.
There needs to be solid multiple peer reviews, error checking and replication, before any claims are made.

Do you agree ?

                                                               floor
                                                                   

[Floor]

OOPS

[conradelektro]

@Floor:

The measurements and graphs are very nicely done. Whatever they say, it is for you to interpret.

I am not interested enough in "permanent magnet machines" to put serious work into it. Therefore I respectfully decline the offer to do any tests personally.

I am working on a ball magnet spinner, which already takes too much of my time. Further I am always working on and off on electrostatic machines. See the attached drawing (which I built partially). It is very easy and versatile to drive a servo with an Arduino (I have the Arduino Due).

Greetings, Conrad

[lumen]

@Floor

I'm not sure if it's correct with the graph  showing "work" as the area under the lines.
I am probably wrong but "work" is distance x force and the graph is showing force at point.

I think the "work" might be more closely related to the length of each line in your graph as it has been recorded as points of force on an increasing scale.

On second thought, it would probably be best to just calculate the distance between each point and the average force of the two points and multiply, save the result and do the same for every point. Then just add all the work (units aren't important at this point) in each set and compare the total work of each set.
Every time I did it this way, it always worked out to even or so close I just considered it equal.
??

[conradelektro]

@Floor

I'm not sure if it's correct with the graph  showing "work" as the area under the lines.
I am probably wrong but "work" is distance x force and the graph is showing force at point.

??

"Work" is essentially the area under the graph (the integral of the graph or curve). One would have to write grams as kilos and millimetres as meter and to multiply the whole with "G = 9.81". But this would just alter the aspect ratio and not the comparison Floor is interested in.

If (a < b) then (a*c < b*c) as long as c is a positive constant.

Greetings, Conrad