Rosemary Ainslie Quantum Magazine Circuit COP > 17 Claims

[Groundloop]

Yep, I think I'll put the cap and neon right at the battery positive pole, with the fast diode right at the coil low end and run the spike feed over to the cap with a transmission line.

The neon flashes bright purple with the 1n4007 in series, I haven't tried it yet with nothing in series, but I was thinking I might go down to 47 uF on the cap for faster cycle time and less current thru the neon.

TK,

>>bright purple

Using the Neon bulb as a high current carrying switch will quickly burn off the neon gas and make the
bulb useless. If you want a high current switch then use glow starters for fluorescent light.
The glow starters for fluorescent light has a neon gas filled bulb with a beam metal switch inside.
The beam metal switch will close by the temperature change from the neon light.

GL.

[TinselKoala]

You are right, I think I've already ruined a couple of them doing this! Fortunately I still have 60 or so new ones and another 30 that I can salvage from my HV Field Yardstick.

The firing voltage goes up and up until after 10 or so fires they don't want to trigger at all ...  But I get nice purple flashes with the Bedini SGM system and it doesn't wear out the neon, just blackens the glass.... weird huh.

Right now I have the cap down to 47 uF, a diode and a 10R in series with the (new) neon, and it's firing bright orange now, not in the purple region any more.

[Groundloop]

You are right, I think I've already ruined a couple of them doing this! Fortunately I still have 60 or so new ones and another 30 that I can salvage from my HV Field Yardstick.

The firing voltage goes up and up until after 10 or so fires they don't want to trigger at all ...  But I get nice purple flashes with the Bedini SGM system and it doesn't wear out the neon, just blackens the glass.... weird huh.

Right now I have the cap down to 47 uF, a diode and a 10R in series with the (new) neon, and it's firing bright orange now, not in the purple region any more.

TK,

A third way to make a feedback circuit is to make a high voltage Joule Thief with a third winding.
The third (L3) winding must be impedance matched to your input battery (Eg. few turns).
The L1 and L2 must have a lot of turns and be impedance matched to you high voltage cap.
Just a thought................. :-)

GL.

[TinselKoala]

Thanks, GL, that circuit is very like some Bedini chargers I've worked with. But I know lots of ways to recirculate power in various circuits. I'm trying to get some kind of worthwhile, or at least interesting, effect from the original Quantum-17 circuit published by, but apparently never actually used by, Rosemary Ainslie and BC Buckley. And which is allegedly being examined Yet Again by Donovan Martin and a team of boffins, to the man, in Cape Town.


Meanwhile, I'm dashing off a short email to my old colleague Rupert:

Hey Rupert

What do you think of this bit of "new physics":

If the photon comprises two zipons then the zipon would be half the size of the photon.  It is proposed that velocity and mass have an inverse proportional relationship.  So, if the photon moves at the speed of light (C) then the velocity of the zipon would be 2C.  And as velocity and mass are inversely proportional so, if the mass of the photon were given as 1, (as a ratio) then the zipon would be 0.5.  If the electron comprises 3 truants then its mass would be 0.5 x 3 = 1.5.  And, if the proton comprises three electrons then, each electron would comprise 0.5 for the quark.  3 quarks having no volume is 0.5 x 3 = 1.5.  Four times bigger for the orbital zenith of the second truant is 1.5 x 4 = 6.  And four times bigger for the orbital zenith of the third truant is 6 x 4 = 24.   The second and third truant only have two dimensions of volume as they manifest within a prescribed space, that merry-go-round referred to in the field description.  Therefore, 3 second truants, having length and breadth is 6 x 6 x 3 = 108.  3 third truants having length and breadth is 24 x 24 x 3 = 1728.  This gives a mass of 1837.5, minus 1.5 for the quarks that have neither volume or mass, giving a total of 1836. Some variation of this number is, no doubt, required to accommodate the spherical shape of the truants, but it's complex – a 2 dimensional sphere.

Pretty remarkable, isn't it? And also a lot of nonsense, of course.

μ = m_p/m_e = 1,836.15267245(75).
http://physics.nist.gov/cgi-bin/cuu/Value?mpsme

Does that difference count as "some variation required to accommodate a two dimensional spherically shaped truant?"
No doubt.

How's that for a hoot?

Cheers-- and I remain
Your old pal,
--TK

[conradelektro]

@TinselKoala:

I played extensively with feedback from a Joule Thief circuit to the battery which is driving the circuit. I tried feedback "from the back EMF of the L2 coil" and feedback with a L3 coil.

The Joule Thief circuit should draw as little power as possible (which means very high impedance coils L1 and L2, high resistance of R1, L3 could have low impedance).

Let's replace the battery with a big electrolytic capacitor, e.g. 10.000 µF.

Now let's do the following test (see attached drawing):

- The electrolytic capacitor (the one which is replacing the battery) is charged to 5 Volt (or any other Voltage which fits the Joule Thief circuit in use) from an external power source (e.g. with a lab power supply), the Joule thief circuit is running.

- Switch off the external power supply and measure the time till the Voltage over the cap has dropped to 3 Volt (with a stop watch and a Voltmeter over the cap).

Do the test with and without the feed back. With the feedback the measured time should be longer, because one recovers some energy.

But I never could get a longer time. The time measured for the Voltage drop always was the same, with or without the feedback.

May be I did something wrong?

Greetings, Conrad

P.S.: the additional diode is not necessary in this circuit, but it would be if feedback comes from the Drain of the transistor (back EMF of L2).