Reactive power - Reactive Generator research from GotoLuc - discussion thread

[wings]

probably already said:

the MOT transformer, has a shunt:
As it is intended to drive a capacitive load, the leakage inductance of the tranformer is deliberately increased by adding a small magnetic shunt between the primary and secondary coils. The inductance is roughly equal and opposite to the doubler capacitance, and so reduces the output impedance of the doubler. This specified leakage inductance classifies the transformer as non-ideal.


http://en.wikipedia.org/wiki/Quadrature_booster
or Phase Shifting Transformers?
with relations to the last Russian youtube with 3 phases it is much easier, because you can mix the phase with another 3phase transformer and as consequence increase the voltage (200V input 220 output)?

By Bucking or Boosting using the next phase.

[gotoluc]

http://en.wikipedia.org/wiki/Quadrature_booster
or Phase Shifting Transformers?
with relations to the last Russian youtube with 3 phases it is much easier, because you can mix the phase with another 3phase transformer and as consequence increase the voltage (200V input 220 output)?

By Bucking or Boosting using the next phase.

Thanks wings,

using 3 Phase would be the easiest  path to a solid state version.

Now all you guys and girls, I've explained enough times what is needed (90 degrees phase shift0!... so go and build it

Thanks for sharing wings

Luc

[wings]

probably already said:

the MOT transformer, has a shunt:
As it is intended to drive a capacitive load, the leakage inductance of the tranformer is deliberately increased by adding a small magnetic shunt between the primary and secondary coils. The inductance is roughly equal and opposite to the doubler capacitance, and so reduces the output impedance of the doubler. This specified leakage inductance classifies the transformer as non-ideal.

the MOT magnetic shunt and his effect that is similar to Thane C. Heins effect :

The weakened energy coupling between the primary and secondary means that a load on the secondary is no longer fully compensated for by increased primary current. Normally, secondary current produces an[/size] mmf[/size] which opposes the primary flux, which the primary then compensates for by increasing its own current draw. Now, however, the secondary flux can drop without the primary flux having to drop too. [/size]
From :http://info.ee.surrey.ac.uk/Workshop/advice/coils/leak/weld/index.html[/size]

[/size]

[tinman]

A way to try and explain this reactive power situation using water and a paddle wheel
In the video,we see water flowing out of a chanel(the waterfall),and onto a paddle wheel.
No matter how much we load the paddle wheel,no reflection or restriction of the water flow will be detected at the output of the water channel(top of the waterfall).But what would happen if we reduce or stop the water flow at the top of the waterfall?. We also know that the paddle wheel would not have enough energy to return all the water driving it,back up to the top of the waterfall.

http://www.youtube.com/watch?v=gKx-Jms624A

A simple test for you all(one i carried out) in reguards to the main's/MOT setup.First,get it to read 0 watt's,and measure voltage across load resistor on the secondary. Next test-place a 1k ohm non inductive resistor on the active of the mains line,befor the watt meter.Now run again,and measure voltage across load resistor on MOT secondary. If we were indeed drawing 0 watts of power,then no drop in voltage across the load resistor should be detected. I could tell you my results,but this is something you must see for your self.

[deslomeslager]

A simple test for you all(one i carried out) in regards to the main's/MOT setup.First,get it to read 0 watt's,and measure voltage across load resistor on the secondary. Next test-place a 1k ohm non inductive resistor on the active of the mains line,befor the watt meter.Now run again,and measure voltage across load resistor on MOT secondary. If we were indeed drawing 0 watts of power,then no drop in voltage across the load resistor should be detected. I could tell you my results,but this is something you must see for your self.

Hi Tinman,
The test you are describing, is it to compare it with the setup which Luc had when he had a MOT on his generator, with a 1 K load on it producing about 10 Watts?
In his L-C circuit the voltage over the primer is not very high, so if you add a resistor in the circuit, you are changing the characteristics of the circuit. If you look at a later setup which Luc did, he used an audio power transformer. He did clearly tel us that the DC resistance should be as low as possible, and said the MOT is therefor not a good example.
If you add a resistor in series, you are reducing the current and creating an offset voltage (lowering the mains), and thus lowering the voltage. This changes the behavior of the circuit you started with (the reactive circuit runs better on a higher voltage, not the opposite).

And in fact I already know the answer, as when I was testing I had a 1 ohm load just for measuring the current on 230 Volt. It did scare me as the circuit seems to draw 2 Amps while the KWH meter says it is running at about 1 Watt (it is an rms Watt meter, but with reactive tests you must always check the scope, that much I have learned already). The AMP claw which I had as well only showed 0.49 Amp. So hmmm? without a scope you cannot rely on meter, unless you know your meters inside out.

To be honest, I did not get the analogy with the water paddle wheel, sorry for that.

And I hope we get a good discussion on this, because I am simply repeating to say the things which Luc says (or at least trying to get as close as possible). I am currently trying very hard to get a generator, since I don't want to do more tests on the grid. I do believe that a good setup can be looped back.

@Luc:
Could you do one more test for us?
Hook up the reactive setup on the generator, the one with the resistor heating up will do just fine. Now I am very curious to see what happens if you start loading the generator, for instance with some light bulbs and using 300 to 500 Watts, or if possible up to a 1000 Watts if you have such a  load. I am not directly interested in the power usage of the induction motor of course, but I am curious if the given power of 1000 Watts of the generator is based upon purely consumed Watts. And if you can get above it, when using ('consuming') reactive power as well. Another test I would love to see is a test in which you hook up 2 of the previously tested circuits, to see if you can draw twice the reactive power, or if there is a limit there as well (if I had a generator these are the kind of tests which I would surely do, it helps in determining the possible applications).