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Overunity Machines Forum



Reactive power - Reactive Generator research from GotoLuc - discussion thread

Started by hartiberlin, December 12, 2013, 04:34:12 PM

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hartiberlin

Quote from: poynt99 on December 13, 2013, 08:12:45 PM
It tells us that the circuit appears capacitive.

However, with 25uF at 60Hz, the most phase shift you can get is about 45º, with the inductance at 0H.

In order to get 90º of phase shift between those two measurement points where i leads v, the inductance would have to be 0H, and the capacitance only about 1uF.

The only explanation I can think of for what Luc is showing us, is that the circuit is highly inductive, and one of the scope channel signals is inverted.

Yes, I agree,
a shortcircuit on the secondary of a MOT will make the MOT a very big choke, maybe having a few Henries of inductance, so I guess this circuit is probably much more inductive than capacitive.... so Luc should really check, if not one scope channel was unawarely inverted...
Could be probably somehwere hidden in the Scope menu..
Stefan Hartmann, Moderator of the overunity.com forum

tim123

Quote from: hartiberlin on December 13, 2013, 02:39:51 PM
Yes, it is valid, as the current can be measured anywhere in the loop...

Hi Stefan,
  it doesn't feel right to me - because we're specifically phase shifting the current / voltage. Your diagram makes perfect sense - but it's quite different from Luc's measurement points.

I think we should probably be measuring both voltage & current (i.e. 4 probes) (EDIT: I mean 3 probes - only 1 needed on shunt):
a) Around the whole circuit - as you suggested, and
b) Around the shunt.

That way it would be possible to compare input with output properly... What do you think?


tim123

Quote from: Farmhand on December 13, 2013, 07:32:16 PM
Nice setup Tim firstly. I like your capacitor box, very useful thing to have. I would like to make a box like that with long throw switches to make sure there is no arcing to "switched out capacitors"

Hi Farmhand, Thanks :)
  The switchbox has been invaluable for many experiments... The switches (ebay specials) are rated for UK mains at 240v, probably would cope with 2-3 that - but I rarely run it at high voltage. As you can see - the wiring inside is well exposed. One of the switches has just mechanically failed (200uF) so I'll have to replace that one day soon. :(

QuoteHere is a couple of clips of my TC sparking and lighting some bulbs...
Cool :)

Quote
I still say if a person has to produce their own AC power, these odd methods of trying to get some free energy won't be free at all. Creating lots of reactive power is not in my opinion a good idea.

Mmmm... I think we need to go back to the beginning, and discuss the aim of the experiment... Will follow up...

tim123

Guys, I think this whole issue is quite complex, and I think we need to start at the beginning, and define exactly what it is we're aiming to acheive / find out.

Is the point of the research to:
a) demonstrate that 'reactive power' can do work.
b) demonstrate that 'reactive power' can be created / consumed by capacitors / inductors.
c) demonstrate that 'reactive power' can be created, and then can do work - all for free
d) find a way to trick the electricity meter / company.
e) something else?

poynt99

Quote from: tim123 on December 14, 2013, 04:34:50 AM
Hi Stefan,
  it doesn't feel right to me - because we're specifically phase shifting the current / voltage. Your diagram makes perfect sense - but it's quite different from Luc's measurement points.

I think we should probably be measuring both voltage & current (i.e. 4 probes) (EDIT: I mean 3 probes - only 1 needed on shunt):
a) Around the whole circuit - as you suggested, and
b) Around the shunt.

That way it would be possible to compare input with output properly... What do you think?

Quote
Tim,

As best I can tell, if I understand Luc's connections, he is measuring power from/to the grid. CH1 is measuring the voltage across the source, and CH2 is measuring the current through the source.

Luc is essentially measuring both the input and output power, the only difference between the two being what is dissipated in the CSR resistor. The volage across the source is essentially the voltage across the LRC network too.

And yes, the current can be measured anywhere in the circuit since it is a series circuit.
question everything, double check the facts, THEN decide your path...

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