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Overunity Machines Forum



Mathematical Analysis of an Ideal ZED

Started by mondrasek, February 13, 2014, 09:17:30 AM

Previous topic - Next topic

0 Members and 30 Guests are viewing this topic.

MarkE

Quote from: webby1 on March 25, 2014, 07:41:57 AM
No it is not.

The fact that you are missing it shows that you do not get it.
Tiresome is as tiresome does.  Show me the multiple potential energy stores in a Torsen or any other style differential.
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PTO's have been around for ages and multiple devices running off of a single drive unit as well.

I don't want the potential to stay in the water, I want it to do work and I want that work to be done through a device of my control.
That's nice.  It does not change the situation that you have in hand.
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What I see when I look at your problem is a source with a diminishing value,, that is all it is, so to use that I need to simply maximize what is available when it is available to do the most work with whatever it is being used for while it can.
That is apparently because despite the number of times that I have explained it to you, you still do not see.  You keep coming back with the idea that if you arrange a lever:  be it as a simple lever or in the form of gears or pulleys, that you can overcome the energy problem.  You have proposed several devices and none of them address the problem.  I can only conclude that is because you do not comprehend the problem.  The only source of energy, and the only source of force that you have available is bound up in the height of your charged column.  I have shown you that even if you arrange a scheme where the force differential is just barely above zero that the force still comes to zero when the columns reach equal heights.  You can have the world's highest gain lever arm and it won't help you.  One would think that you could see this from your own contraption where you admit that when the two arms each come level to the horizon the machine stops.

Magluvin pretty much gets the problem:  In order to efficiently transfer between the columns, you have to hold N close to one.  You must drain the energy out of the first column by converting it into another form and then use the energy in that other form to fill the second column. 
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What part of "you can not destroy energy" do you really not understand?
Tom, heat is energy.  When it is the same temperature as the environment it is not useful energy.
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Energy????, call it what you want but it describes a packet force over some distance,, that "work" can be converted into any other value of force and distance so long as they are the same packet size.
Energy isn't what I call it.  It is the integral of F*ds.  And if you think all useful energy always remains useful energy then you do not understand the basic concept of efficiency.
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I do not care about energy, does not bother me at all,, I have always looked at the actual force and the actual distance the actual angles and all of that actual stuff.  All the formulas do the same thing with different names and conventions and, well all those funny little characters meaning this , that, and the other, but those formulas must always change to meet what people like me actually do, that is not the other way around,, if I am doing something that the formulas states I can not,, then the formula changes I do not suddenly stop being able to do what ever it is I am doing.
Wayne Travis' fraud is all about his false claims of being able to generate unlimited amounts of free energy.  It is a fraud that you staunchly support.  You present yourself more and more as unfamiliar with and unable to grasp the fundamental concepts involved.

MarkE

Quote from: webby1 on March 25, 2014, 02:38:13 PM
Hmmmm,, I wonder what it is that I am saying, the big part that you do not seem to get nor understand.
A lever does not convert the energy into another form.  A lever multiplies force at a cost of distance or distance at the cost of force.
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The column of water is only a store of potential, drain the store, convert that and then re-use it,, DOH!
If you want to defeat the N*(X/N)2 problem you have to convert the form of the energy.  I have explained this many times.  You act as though you do not grasp this concept.
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Drain the store using more than 1 item even,, it is all the same thing.
No, you have to convert the energy to another form.  You cannot keep the energy in potential form without facing the N*(X/N)2 problem. Do the math.  Oh, that's right, you say you don't know how to do the math even though I have shown it to you many times.
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This is what I have been saying.
You keep repeating invalid ideas.
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If you do not understand what the diff does, that is fine,, that is more in my area.
We may be witnessing Dunning-Kruger exemplified.
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I would really suggest you fix up your spreadsheet,, not to make any changes, and I do not think all of the errors affect things much, but it is your work that others may be looking at.
You have not identified any errors in the spreadsheet.  If you or anyone else identifies an actual error then I will fix it.
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If you are not worried about it no problem for me either,, I just have to fix your errors and then move on as I am using it for a guide on how to go about doing this stuff, and yes the errors are that obvious.
Then you should have no problem identifying these supposed errors that no one else has identified.  What are the odds that you can't anymore identify an actual error than you have been able to come up with a solution to your two cylinder lifter energy loss?

MarkE

Quote from: webby1 on March 25, 2014, 03:49:24 PM
This is interesting,,

Oh,, width is not height by the way,,
Red is not blue.  So what?
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Program problems,, That makes more sense then that you did not see any errors.

For some reason when I copy and paste sometimes I am getting this
=0.5*cir_mm_m_to_N_1*(AR2CirArea_1+AR2_3WaterVol_1+AR2CirArea_1+AR5CirArea_1+AR3CirArea_1+AR7CirArea_1+Riser1WallCirArea_1+cir_mm_m_to_N_1+Riser3WallCirArea_1)*(ST0_AR_Height_1*mm_to_m_1)^2

When I copy this

=0.5*cir_mm_m_to_N_1*(AR2CirArea_1+AR3CirArea_1+AR4CirArea_1+AR5CirArea_1+AR6CirArea_1+AR7CirArea_1+Riser1WallCirArea_1+Riser2WallCirArea_1+Riser3WallCirArea_1)*(ST0_AR_Height_1*mm_to_m_1)^2
You still haven't pointed out any alleged errors in the R4 spreadsheet.  You've only indicated that between you and Open Office you are having problems making whatever changes you would like to the R4 spreadsheet.  The formula that you are copying is the named cell ST0_Energy.  You can simply refer to that by name.  For example:  '= ST0_Energy*1'.  That particular cell calculates the stored energy potential in the three columns of water in State 0. 

MarkE

Quote from: webby1 on March 25, 2014, 04:00:15 PM
What is force,  What is Energy, What is distance, What is stored potential?

Does a lever use pressure?

Does gravity do any work all by itself?

A unit quantity of Energy is just that, there is no "form" to it.

You wont get this but,

You need to be able to identify both sides of a coin, otherwise you can only say heads or not heads, and this may be just fine and dandy and you may be able to make all sorts of heads and not heads observations, but then the coin  is flipped and lands on its edge,, since it is not heads that is all you can call it, not heads.

See the problem.
You present yourself as unfamiliar with elementary physics.  Energy does indeed take multiple forms.  In the mechanical world the two forms are:  potential energy, and kinetic energy.  Potential energy is the energy that results because of something's position within a field.  Kinetic energy is energy that something has because of its motion.  A spinning flywheel of some defined inertia and spin rate may have the same quantity of kinetic energy as the quantity of potential energy stored in a suitable compressed spring, but the forms of energy are completely different.

MarkE

Quote from: webby1 on March 25, 2014, 05:03:23 PM
=Riser2Height+VerGap+RiserWallThickness

I am wondering if this issue is the same as the copy and paste issue, that is with the program I am using.
The risers are modeled using a uniform material thickness for both the tops and the sides.