Mathematical Analysis of an Ideal ZED

[MarkE]

Sorry MarkE, could you tell me which post has been updated?

#667

Quote from: mondrasek on Today at 05:28:21 PM

    MarkE, the initial payload is slightly below the maximum buoyancy Force in State 2.  And the payload also declines linearly as the system lifts up.  The payload "slug" of water does not sit on the piston at the end of State 3.  It has been allowed to run off unimpeded across the top surface shown that includes the bore.  The correct Energy equation reduces to .5*Fmax*S.

You are still subject to the N*(X/N)² tyranny.  Let's say that you set-up your payload such that it runs off at the rate of 64.649N/m to match the rate at which the riser lift force runs down, then the  Wpayload = 0.30078N - 64.649N/m.  Now perform the integral math on the work you impart doing the lifting:

E = integral( F*ds )
F = 0.30078N - 64.649N/m
integral from 0 to 4.653mm is:
0.30078N * 0.004653m - 0.5 * 64.649N/m * (0.004653m)² = 0.7mJ

The internal change in energy from State 2 to State 3 was 1.024mJ.  So you are still stuck with a 30% loss.

[mondrasek]

   Hi,
       I tried with a bit of light oil over water and it's ok if you don't get any revs up.
   Once you try and increase the rate of doing work of course you just emulsion.
    When you put oil over water in your ZED you get a totally different beast than
    when it's got air over water.
                                        John.

Another reason to keep the difference in the Specific Gravities of the two working fluids as large as possible?  Or, is it a showstopper that means a gas, while lossy as far as Energy is concerned, has an advantage when Power is the ultimate goal?

[MarkE]

Another reason to keep the difference in the Specific Gravities of the two working fluids as large as possible?  Or, is it a showstopper that means a gas, while lossy as far as Energy is concerned, has an advantage when Power is the ultimate goal?

The irony is that the force multiplication goes up with the relative SGs, but the efficiency goes down.  The best ZED is not a ZED at all, but an ordinary hydraulic lift.

[mondrasek]

#667

Thanks!

Now back to the 3-layer ZED.  Which one do you want to check?  We need to calculate the Energy that left that system due to the rise.  Then I think the Energy Balance Analysis is complete.

[MarkE]

Thanks!

Now back to the 3-layer ZED.  Which one do you want to check?  We need to calculate the Energy that left that system due to the rise.  Then I think the Energy Balance Analysis is complete.

Have you downloaded the spreadsheet?  Everything you want should be in it.  The ZED is a piece of useless junk.  I don't know where you obtained OU numbers, but it certainly is not reflected in the ZED.  The "ideal ZED" using incompressible fluids, once you've paid all the energy to prepare it and charge it up, just acts like a linear spring.  If you make one with  compressible "air" it acts like a variable rate spring with additional loss.