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Overunity Machines Forum



Recover energy from gravity

Started by rc4, February 15, 2014, 05:21:41 AM

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rc4

ok, but for the #44 post ? air container can be attached directly to the water container, I think it's the same.

Gabriele

Each cycle you move the lever the air container lose his potential energy untill he is completly out of the water

rc4

if I use only one container and turn it around like drawing shows, in half part I don't have more energy ?

rc4

Maybe with electric like that ? V can be multiplied with external iron. At secondary, reluctance is divided by 2 because there are 2 iron in parallel. If reluctance is divided by 2, there are 2 fluxes created by I, so this multiplied voltage by 2, no ?

With number of turns at primary = number of turns at secondary:

Input: give V*I
Output: recover 2V*I

rc4

V is divided by 2, so at primary I need VI/2 and at secondary I recover VI/4 ?

So if I place source in the middle with 2 charges, I give VI/2 and recover VI ?