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Overunity Machines Forum



Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

Started by madddann, March 26, 2014, 09:42:27 PM

Previous topic - Next topic

0 Members and 66 Guests are viewing this topic.

pmgr

Quote from: MileHigh on June 14, 2014, 02:28:40 PM
So, I am going to repost the screen cap of the QEG primary voltage and current from the FTW clip.  See if the two of you can put it all together and explain the waveforms in simple terms, and relate that to the "events" that you see in the waveform.

As a reminder for the readers, yellow is the cap voltage and blue is the current.

MileHigh

I will give a little bit more input here. Take a look at the attached waveforms which I posted earlier. At integer rotation numbers (e.g. 181, 182, 183 in the graph), the rotor is aligned with the stator tip (0deg, 90deg, 180deg, 360deg). This is exactly when you see the dips in the primary current....
Also note that when half way in between two stator tips (45deg, 135deg, 225deg, 315deg), you see an extreme in the secondary current....

8) PmgR
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MileHigh

You guys basically got it.

Here is the clip:  https://www.youtube.com/watch?v=Jhd0Ebygriw

I will do a repost of the screen capture and explain it in terms of energy and cause and effect.

MileHigh

MileHigh

The entire process can be explained by looking at the the positive sloped portion of the voltage waveform in the center of the scope display.  The exact same thing happens in the reverse direction when the voltage waveform has a negative slope.

Looking at the LC resonator from the capacitor's viewpoint, you can see the current is leading the voltage by a bit less than 90 degrees.  It's a little less than 90 degrees because of the resistive losses and resistive coupling into the light bulb load through the transformer action.  We will ignore that to keep it simple.

At 3.4 divisions, the capacitor is fully charged and the blue current has stopped flowing.  That's the start of the discharge cycle of the cap into the variable-inductance coil.

You can see how the current takes off at a very high rate at 3.4 divisions.  This is due to the fact that the inductance is low, and you know that low inductance happens when the rotor is not aligned with the poles.

The cap continues to discharge and at the first current "peak" it starts to decrease.  That's when the rotor is starting to align with the poles and the effective inductance starts to increase.  So the current decreases because of the conservation of energy, it has to decrease because the magnetic energy in the inductance is rising slowly, and the inductance is increasing much more quickly than the magnetic energy is increasing.  The only way for the energy to be conserved is for the current to decrease.  This is like the spinning figure skater extending his or her arms and slowing down.

Again:  Note that during this whole time the capacitor is still discharging into the inductor.  So although you see the current decreasing, the magnetic energy stored in the inductor is still increasing.

Note that the slope of the capacitor waveform decreases when the inductance starts to increase, which makes perfect sense.

So the bottom of the current trough at 5.2 divisions or thereabouts corresponds to when the rotor is aligned with the poles in the QEG toroid.

At 5.0 divisions we see that the capacitor is discharged.  This is the "hand off" point where the variable inductance takes over and starts to dump its magnetic energy into the capacitor.

Now you have a similar "contrarian" process taking place.  Starting at 5.2 divisions, you see the current in the variable inductor increasing, but the amount of magnetic energy is decreasing and being used to charge the capacitor.  This is all due to conservation of energy one more time.  This is the time when the rotor is starting to leave the poles and go out of alignment again and therefore the value of inductance is decreasing.

Then at about 6.0 divisions, the rotor moves out of alignment with the poles and the inductance drops dramatically.  At the same time, the inductance is running out of stored energy, and the voltage on the capacitor is very high, meaning its absolute equivalent resistance is high, and so the current drops like a stone.

At about 6.7 divisions the inductor is fully discharged, and the capacitor is fully charged, and the whole process starts all over again, but in the opposite direction.

So, sorry for the long winded explanation but I think it's a good exercise, especially for the QEG builder-lurkers.

In simplified terms we are still looking at an energy exchange like any LC resonator.  The current may appear to have a funky double-peak waveform, but that's just a fake-out from Mother Nature.  The magnetic energy and electrostatic energy is still cycling back and forth in a smooth fashion.

Anyway, to be conservative, this would have to be verified on the bench.  You would want to set up something to verify the angular position of the rotor.  However, the logic and the simulations indicate this, so I will be so bold as to suggest that it would just be a formality.

MileHigh

MileHigh

Pmgr:

Can you reduce the size of your graphic to make the page more readable?

Thanks,

MileHigh

P.S.:  Thank you!

MileHigh

Now a brain teaser for all the QEG emo-builders!  (or anybody else except those that voluntarily disqualify themselves!)

What's an equivalent for an infinitely large capacitor?

What's an equivalent for an infinitely large inductor?