Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[TinselKoala]

Now let's take a look at Luc's scopeshot and analyze it.

First, it shows a Voltage and a Current trace that are, to first order, sinusoidal, and 90 degrees of phase shift, approximately.

We know that if you do the instantaneous multiplication of V and I you get an accurate and true _instantaneous power_ curve. That is what is shown as the Red Math trace. This is correct. At any instant you can look at that math trace and see what the actual power is at that moment.

But is this also the "average" or mean power that can be dissipated in a load? We know how to find that, from the RMS values of sinusoidal V and I:

V _rms x I _rms x cosine (phase angle) = average power

Right?

Solving this equation from the scope's reported V_rms and I_rms and the 90 degree phase angle.... what is the result?

Is this result equal to the "Math rms" value on the scope screen? Which value is correct for the power represented by the scope V and I traces?

[Angelic]

Thanks for the input on my salvaged part. I will give it a try. And Tk I do watch all of your videos. Next time I will get my image size right.

[TinselKoala]

Thanks for the input on my salvaged part. I will give it a try. And Tk I do watch all of your videos. Next time I will get my image size right.

You're welcome, and thanks for watching!
It looks like that part has already been used for some "nefarious purpose", it seems to be rewired somewhat.
If you haven't already found it, the flyback HV section in the Sony TV circuit diagram is at the very lower left corner. It's not too helpful though; I think that one is a single FBT design.


ETA: You can use the exact same circuit I am using here, except use IRFP260n mosfets and around 600 nF tank capacitance. Wind 6-8 turns of heavy wire around the exposed leg of the ferrite core of the FBT and connect that as the "loop". But be very careful... only one mistake is all it takes and you really will be "angelic"...    .

[TinselKoala]

We also know another way to get to the average power shown on Gotoluc's scopeshot, and that is to _integrate_ the Instantaneous Power function (the red Math trace) over a time interval (answer will be in Joules), then divide that value by the time (result will be in Joules per second, ie Watts).  What do you get when you do that? Does that answer resemble the "Math RMS" value?

[Angelic]

TK this is how it was wired coming out of the unit (Sony KP-5000) a real dinosaur. Pull it up and you will see what I mean.