The Bessler Wheel, mystery solved.

[gurangax]

@gurangax
One weight on a lever provides torque on an axle ; at the end of the axle at the 2 Levers the torque is halved and because of the different length of these levers , the forces that they apply to the levers of the main shaft are not equal . Therefor they don't cancel each other and there is a resulting torque that rotates the main shaft. Please do not judge it based on his replication, but on the idea.
https://www.youtube.com/watch?v=OWRyYYX7JxE
Do you think this is possible?

I don't see how that will work, probably using a motor inside. If it was caused by gravity it should accelerate, instead the velocity is just the same.


regards

[vineet_kiran]

Action and reaction are equal and opposite.  If you take vector sum of these two forces it accounts to zero.  Which means the mass shouldnot move at all.  But why a mass moves when you apply force on it?

You people are just confusing the issues. For a static force the vector sum of all forces (including action and reaction) sum upto zero. Hence the mass doesnot move.  In a moving mass you have to resolve the forces separately for the mass in motion and the driver causing motion.  Then you will get the direction of net force.  If you have doubt,  purchase a engineering mechanics book and read it.

You can magnify a static force hence static energy by using a lever.  For example think that you are breaking a wall using levers.  If you use shorter arm lever, you have to spend lot of energy to break the wall. But if you use a very long length lever you can break the wall easily. In both cases output energy required is the same since no movement is involved but input energy will be very less in the second case (ie., with longer lever arm). 

In the above instant both action and reaction are static since no movement is involved.  Which means that to magnify static energy, both action and reaction have to be static.


In a moving system, for example a wheel, the action will be moving in one direction causing the wheel to rotate but the reaction will be stagnant in opposite direction which will be provided by the bearing which in turn slows down the action.

Hence if you make the bearing also to rotate in opposite direction, you may get magnified energy from the wheel since the reaction force further enhances action instead of slowing it down


To sum it up :


a) For stationary energy to be magnified, both action and reaction have to be stagnant.

b) For moving energy to be magnified (overunity) both action and reaction forces have to move in opposite directions.

http://www.lhup.edu/~dsimanek/museum/overbal.htm

None of the wheels shown in the above link work because, none of these wheels consider reaction forces. If theses designs are intelligently modified so that action and reaction forces move in opposite directions, then there is a possibility that all  these wheels can become perpetual wheels.

[zoelra]

Quote from  Newton II Today at 03:26:32

Action and reaction are equal and opposite.  If you take vector sum of these two forces it accounts to zero.  Which means the mass shouldnot move at all.  But why a mass moves when you apply force on it?

A net zero force does not necessarily mean no movement, but it does mean no acceleration.  If you lift an object at a constant speed you are countering the weight of the object with your own hands.  The net force is zero.  If an object is sitting on a table and there is friction between the object and table, and you provide just enough force to overcome the friction, the object will move at a constant speed.  Again the net force is zero.

How to handle the effects of accelerating within a gravity field may be one of the ingredients in finding a working solution. 

[camelherder49]

Just in case nobody noticed, someone must be wrong in their description
of force/vector etc.

[MarkE]

Action and reaction are equal and opposite. 

Correct.

If you take vector sum of these two forces it accounts to zero. 

Correct.

Which means the mass shouldnot move at all.

Incorrect.

But why a mass moves when you apply force on it?

B E C A U S E, in that case the reaction force is equal to mA. 

Thanks for playing.