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Overunity Machines Forum



The Bearden MEG

Started by Smudge, May 09, 2014, 11:10:27 AM

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Neo-X

Quote from: Smudge on May 10, 2014, 03:12:12 AM
Thanks for the encouragement.  I have lots more on my computer having spent the last 20 years studying OU.  I am too old and don't have the facilities for doing serious practical research but I do have a brain and have written many theoretical papers.  I hope these will steer others in what I think is the right direction.  Look out for more papers soon.

20years wow thats too long.. Me i think im studying ou for 15 years starting from 2nd year high school and now im  29years old still studying ou.  :)

Smudge

Quote from: vasik041 on May 10, 2014, 04:59:27 AM
Hi Smudge,

I am also studding this subject for some time and
perhaps you find attached document interesting  ;)

Regards,
V.

Hi V.

The original Bearden MEG used huge output coils that would have significant self capacitance and could have formed an LC resonant circuit at his frequency.  Certainly there is some resonance there because his voltage outputs were close to sinusoidal yet the input drives were switched pulses.  I think that resonance (which would appear as AC flux not coming from the drive circuit but from the AC current in the tank circuit) is important in sweeping across the non-linear core characteristic.  Another thing I found in playing with metglas cores is that they have a mechanical resonance that can be excited via magnetostriction (because metglas is magnetostrictive) and that too could account for the resonant feature.  In fact I have another paper that looks into that mechanical resonance and posits that the OU could come from the Vilari Effect, I will dig it out and post it.  My calculations showed that the AC flux was small in comparison with the magnet flux, so the perception that the switching coils switch all the magnet flux in each half on and off is erroneous.

In any coil the changing flux through it is directly related to the time integral of the voltage waveform, so you can always measure the voltage and calculate that flux change.  The simple formula is
int(V).dt=NAB where N is turns, A core area and B is the change in flux density.  That will give you a measure of your AC flux.

I'll look at your paper and comment later.

Cheers

Smudge


Smudge

Quote from: Neo-X on May 10, 2014, 05:09:56 AM
20years wow thats too long.. Me i think im studying ou for 15 years starting from 2nd year high school and now im  29years old still studying ou.  :)

Well I am half a century older than you (I'm actually 80 years old) and spent all my working life in the UK defence industry on electromagnetics.  I actually witnessed a runaway event where some transitor equipment powered from a mains operated bench DC supply somehow managed to create its own DC voltage in excess of that supplied so the voltage and current gradually increased until the power transistors blew.  My only explanation at the time was that the equipment fed back some RF into the bench supply to "capture" the voltage control there and take it over, but that was never proved.  It happened at different factory locations using different bench equipment.  The reason it occured was the production factory had sourced its power transistors from a new (and cheaper) supplier, and these although having the same 2N numbers were completely different inside and had a much higher frequency cut-off.  They were indeed creating parasitic oscillations and the quick-fix demanded by the production factory was simply to revert to the old supplier (hence no paper work needed to implement what would have been the proper approach to include extra components to stop the parasitics).  I always had the sneaking feeling that I had witnessed an OU event associated with the magnetic components (transformer cores) operating outside their normal envelope.

Farmhand

Is this statement from the PDF actually true ? A negative resistance represents a source of energy ? I'm not so sure it does.

QuoteOf interest to OU researchers is the concept of negative resistance, since this represents a
source of energy rather than a sink
. The next figure shows the F v I plot for an inductor
shunted by a negative resistor.

..




Farmhand

From Wiki - http://en.wikipedia.org/wiki/Negative_resistance

QuoteProperties[edit]

Figure 2: The IV curve of a theoretical negative resistor
Figure 2 shows a graph of a negative resistor, showing the negative slope. In contrast to this, a resistor will have a positive slope. Tunnel diodes and Gunn diodes[2] exhibit a negative resistance region in their IV (current – voltage) curve. They have two terminals like a resistor; but are not linear devices. Unijunction transistors also have negative resistance properties when a circuit is built using other components.

For negative resistance to be present there must be active components in the circuit providing a source of energy. This is because current through a negative resistance implies a source of energy just as current through positive resistance implies that energy is being dissipated. A resistor produces voltage that is proportional to the current through it according to Ohm's law. The IV curve of a true negative resistor has a negative slope and passes through the origin of the coordinate system (the curve can only enter the 2nd and 4th quadrants if energy is being supplied). This is to be compared with devices such as the tunnel diode where there is no source of energy within the device. The negative slope portion of the curve is entirely in the first quadrant and the curve passes through the origin into the third quadrant, never entering the second or fourth quadrants.[3]

History[edit]

In early research it was noticed that arc discharge devices and some vacuum tube devices such as the dynatron exhibit negative differential resistance effects.[4] If the screen grid is at a higher potential than the plate electrode the secondary emission from the plate will result in large numbers of electrons being attracted to the screen grid. If the plate voltage is reduced further the plate current to the screen grid will increase. This effect is a negative resistance and when a screen grid tube is operated in this negative resistance region it is called a dynatron.[5] Small-signal transit-time effects in vacuum tube diodes can result in alternating positive and negative conductance. This occurs when the transit time of the electrons is slightly over one cycle of the AC signal.[6] Practical and economic devices only became available with solid state technology. The typical true negative impedance circuit—the negative impedance converter – is due to John G. Linvill (1953)[7] and the popular element with negative differential resistance—the tunnel diode – is due to Leo Esaki (1958).[8]


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