KARPEN PILE

profitis · July 24, 2014, 05:51:02 AM

So the the h2 was burned up by Ag2O in this preliminary correct pomodoro?this just to prepare cathode right?

pomodoro · July 24, 2014, 07:47:41 AM

Correct. This test is for a few days only. To see how it compares to the other cell. Later cell will be used to test out other cathodes.

It is discharging at the moment. Earlier today, after a few hours of discharging ,I allowed it to charge up. After a few hours it never went higher than 395mV and hovered around the 391-395 mark. Tomrrow I will allow it to charge up again. Anything near 900mV will mean that oxygen has crept in again.

profitis · July 24, 2014, 08:26:57 AM

Going up as high as 1.1v doesn't necessarily mean air is getting in pomodoro I've done this hundreds of times with nickel/Ag/NaOH.if the anode is totaly saturated with H2 and the whole thing sealed off properly voltage can climb pretty high.I used to discharge overnight,rest the whole afternoon,measure in the evening,discharge overnight,rest whole day,measure in evening.you must give the thing ample rest after long run discharges in order to auto-resaturate.

profitis · July 24, 2014, 08:40:43 AM

You must make sure that you have a visible large hydrogen bubble in the gadget2 test so that we can see if it shrinks in size over time.that will mean air is creeping in.

pomodoro · July 24, 2014, 09:34:10 AM

Quote from: profitis on July 24, 2014, 08:26:57 AM
Going up as high as 1.1v doesn't necessarily mean air is getting in pomodoro I've done this hundreds of times with nickel/Ag/NaOH.if the anode is totaly saturated with H2 and the whole thing sealed off properly voltage can climb pretty high.I used to discharge overnight,rest the whole afternoon,measure in the evening,discharge overnight,rest whole day,measure in evening.you must give the thing ample rest after long run discharges in order to auto-resaturate.

1.1 v is for nickel though. This is different animal. I'm positive that the pd electrode surface and H2 will reduce any oxygen given time, but if it was up to the cell to do simply by discharge, it could take a very long time. A mg of stray O2 requires 12 coulombs to reduce. At a typical 12 uA, diffusion limited current that's a million seconds.