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Conical Pulley Drive results in overunity?

Started by vineet_kiran, July 28, 2014, 11:44:13 AM

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vineet_kiran

Quote from: Newton II on July 29, 2014, 06:43:43 AM

The top portion of the cone describes bigger diameter, so it will move with greater speed than bottom portion of cone having smaller diameter.  This will result in two different velocities of the belt at top and bottom portion.  Which in turn may result in slipping or distortion of belt at top portion because belt is a single piece and it cannot move with two different velocities.  So, enhancement of torque which you expect because of larger diameter at top portion,  will be lost due to slipping.  So, I think
you will not get any enhancement of torque or power using a cone shaped pulley.



It seems world is full of cranks.

When belt takes the form of cone under tension,  it behaves like intgral part of the cone because it will be tightly held to the cone.  So in whatever fashion the cone moves,  belt follows the same pattern.  Speed, which is RPM remains same for top and bottom portion  of the cone but only velocity which is dependent on diameter, will be higher at top portion and less at bottom portion.  Since belt becomes part of the cone due to its flexibility, it will move with same velocity as the cone at top and bottom portions of the cone. This is the difference between rigidity and flexibility.  Hence there  is no chance of slipping or distortion of the belt.

If efficiency of drive is reduced because of tension, stretching etc., it will be compensated by gain in torque because of higher diameter of cone rotating with same speed as prime mover.


Quote from: Newton II on July 29, 2014, 06:43:43 AM

"Failure inaugurates highway for success "-  Lord Perpeculum



After you die,  if you meet Lord Perteculum in heaven or hell, please tell him that he is a fool.

MarkE

Quote from: vineet_kiran on July 29, 2014, 09:20:19 AM

It seems world is full of cranks.

When belt takes the form of cone under tension,  it behaves like intgral part of the cone because it will be tightly held to the cone.  So in whatever fashion the cone moves,  belt follows the same pattern.  Speed, which is RPM remains same for top and bottom portion  of the cone but only velocity which is dependent on diameter, will be higher at top portion and less at bottom portion.  Since belt becomes part of the cone due to its flexibility, it will move with same velocity as the cone at top and bottom portions of the cone. This is the difference between rigidity and flexibility.  Hence there  is no chance of slipping or distortion of the belt.

If efficiency of drive is reduced because of tension, stretching etc., it will be compensated by gain in torque because of higher diameter of cone rotating with same speed as prime mover.



After you die,  if you meet Lord Perteculum in heaven or hell, please tell him that he is a fool.
NewtonII is correct.  The belt does not take the form of the cone.  Given some amount of tension in the belt: a portion of the top part of the belt in contact with the top of the cone moves with that portion of the cone, another portion beneath that slips, and the rest does not even contact the cone.