drawing energy from parallel realities

[Marsing]

Hi Marsing. Milan stated in his video that he is swapping the capacitors around from test to test to take into account
small differences in capacitance values compared to the nominal values.
All the best...

Hi all,

i didn't watch the video yet, and the steps described by milan are not so clear to me (step 2). so i assume it just charge/discharge between 2 caps.

when trying to decode the steps with condition all caps have same capacitance, i have :

Step 1  charging C-source from external source and discharging C1 and C2
   --> charge C-source then discharge to C1, charge C-source discharge to C2, here C1 and C2 will have 12volt
   
step 2  disconnecting C- source from external source
   --> after step 1 complete, C-source was still connected to PowerSpply and then disconnecting, means C-source has 24 Volt.

step 3  Discharging C-source  to randomly chosen  target capacitor C1 or C2.
   -->  say C1 win, differences C1 and Cs -->  24v(Cs) - 12v(C1):= 12v, then divided by 2 (because we play with 2 caps):= 6v, finally lower voltage + 6v := 18 volt. or with simple way,   CS,C1 voltage :=  Cs + C1 / 2  = (24 + 12)/2 = 18 volt.
   Say in other case C-source will be discarged to both C1 and C2 ( Cs,C1,C2 are in parallel), Cs+C1+C2 /3 = (24+ 12+12)/3 = 16v , final result CS, C1,C2 := 16 volt.
   
i see no free ticket, with this steps we will always get 18 volt. 
but again, i did not yet watch video, so please someone explain step 2.
All the best too. 
..

[Mancha]

[

step 3  Discharging C-source  to randomly chosen  target capacitor C1 or C2.
   -->  say C1 win, differences C1 and Cs -->  24v(Cs) - 12v(C1):= 12v, then divided by 2 (because we play with 2 caps):= 6v, finally lower voltage + 6v := 18 volt. or with simple way,   CS,C1 voltage :=  Cs + C1 / 2  = (24 + 12)/2 = 18 volt.
   Say in other case C-source will be discarged to both C1 and C2 ( Cs,C1,C2 are in parallel), Cs+C1+C2 /3 = (24+ 12+12)/3 = 16v , final result CS, C1,C2 := 16 volt.
   
i see no free ticket, with this steps we will always get 18 volt. 
but again, i did not yet watch video, so please someone explain step 2.


Hi Marsing,
you made complete wrong calculation.
Before  random discharging to C1 or C2  there  is Cs=24 V  and C1= 0 V ; C2 =0 V.
Let say C1 wins, then will be  Cs =12V ; C1 =12V  ; C2= 0 V
But we are getting Cs=18V ; C1=18V  ; C2= 0V
Cheers,
Milan
..
[/quote]

[Marsing]

Hi Marsing,
you made complete wrong calculation.
Before  random discharging to C1 or C2  there  is Cs=24 V  and C1= 0 V ; C2 =0 V.
Let say C1 wins, then will be  Cs =12V ; C1 =12V  ; C2= 0 V
But we are getting Cs=18V ; C1=18V  ; C2= 0V
Cheers,
Milan
..

Hi Milan,

Like i said before, i didn't watch your vid, and the steps description are not so clear. So that was a calculation.
Explanation above is better and easy to understand what you want to express , and yes that is an anomaly.
what if with 3 or 4 C-target,  is the voltage after discharging still 18 volt or what?

All the best

..

[Mancha]

what if with 3 or 4 C-target,  is the voltage after discharging still 18 volt or what?

Hi Marsing,
I do not know the answer  yet. We are busy with other projects. We are R&D Lab funded from  outside  for some energy  research. But some of them  we are doing  alone  (this project is funded by me)

We did not make test yet, by logic  I beileve that we can draw 1/n charge from other realities where "n" is the number of created  realities. but it is not proven  with experiments yet.
All the Best,

[TinselKoala]

Let me see if I am understanding you, and can work through some example math.

Let us assume that all three capacitors are 1 Farad caps. This makes the example calculations easier but the results should hold true no matter the actual capacitances.

So we have C_s = C_r = 1 F, and Vc_s init = 24 V and Vc_r init = 0 V.

Computing energy, we have E(C_{s init}) = CV²/2 = 288 Joules. Then after discharging into C_r, we have both caps at 18 V so E(each cap) = CV²/2 = 162 Joules.

But only E(C_{s init}) - E(C_{s final}) = 126 Joules have been removed from C_s. Yet apparently 162 Joules have been added to C_r.

Right so far? Please check my work and let me know if I've made any errors so that I can correct them (and my understanding) right away.

However.... the "unaccounted for" difference of 36 Joules is a bit over 20 percent of the total measured value on each cap, or 10 percent of the total on both caps,  after the discharge. Yet most ordinary electrolytic capactors have 20 percent tolerance in their nominal values. IOW it would only take a relatively small difference between the _actual capacitances_ and the nominal capacitances of the caps involved, to account for the entire discrepancy in the measurements of energy on the capacitors. A difference that is small enough to be within the tolerances of ordinary electrolytic capacitors.

So I think one thing that is definitely needed is an accurate, separate, determination of the exact capacitance values of the caps used in the experiment. Then the experiment should be repeated a dozen times, with accurate recording of the start and finish voltages, then some statistical tests can be applied to the data to see what is _really_ going on. But first and foremost we need to be using _exact_ actual capacitor values, not the nominal label values, in the energy calculations.

"We did not make test yet, by logic  I beileve that we can draw 1/n charge from other realities where "n" is the number of created  realities. but it is not proven  with experiments yet."

By logic... you have no data that should cause you to believe anything at all about "other created realities", and proper experiments cannot "prove" but only disprove hypotheses.