Magnet Myths and Misconceptions

[Pirate88179]

Bill - I don't understand any simpleton dribble Sorry!!! Please go and actually read the posts, you obviously have not because you're rambling PIFFLE!!!

So I guess that is a big no then.  You did not understand right?

Good to be able to admit that.

Bill

PS  I not only read the post, I copied it for you in my question.  I tried to make it easy for you.

[Pirate88179]

Waitress, could we please get some coffee for Joel over here to go with his humble pie?

Thank you.

Bill

[EMJunkie]

PS  I not only read the post, I copied it for you in my question.  I tried to make it easy for you.

Well Done Bill! Have a wee sleep after that one 

[EMJunkie]

Pencils down.  The answer to the problem as stated is readily solved as below:

I from 0s to 5s is:

I₀  + 3.5A/s

I beyond 5s is:

I₀  + 17.5A + 2.5A/s * (T-5s)

Mark - I will say, this is perhaps the most constructive post on this thread!

Well Done! You too now deserve a wee sleep 

You know, I have just the slightest little bit of respect for you now - You put MileHigh to shame here in one post! Well done!

[MarkE]

Mark - I will say, this is perhaps the most constructive post on this thread!

Well Done! You too now deserve a wee sleep 

You know, I have just the slightest little bit of respect for you now - You put MileHigh to shame here in one post! Well done!

You have shamed yourself.  Contrary to your claims, the current function versus time is easily determined.  It does not depend on the inductor package or any of the other red herrings that you threw out.  It depends on the integral of V/L dt as MH posted.