Sum of torque

[EOW]

I need a negative pressure, it is possible to do with an attraction from the left side.

All the device turns, even green line and yellow line.

[EOW]

laws 1/x^0.5 and 1/x^0.3

[EOW]

The idea is to use balls1 attract with a law of 1/d². In the container I put a lot of balls2 (empty) but not attract, if I was inside water under gravity I could say these balls2 are bubble with gas inside. I calculate the torque on the black arm around the green center, like balls2 give the complementary pressure I have no torque on the black arm around the green center. Now, the force in the green center is 1.5555 N and if I place the green axis at 11 meter from the center of rotation of the device I have 11*1.5555 = 17.11 Nm. But the torque on the left side is not 17.11 Nm it is 18.197 Nm. Look at the integrals.

The function is (1/3-2*(1/3^2-1/x^2))

[EOW]

Or maybe like that with disks or spheres, I think disks are better

The volume of the blue ball is:

H*H-((H/-2*R)²/sqrt(3)*2*pi*R²) = constant = 0.0931 H² with R the radius of the white ball, the result don't depend of the radius of the white ball.

There is a up force on the object. The disk (2d) 7.519 % than a square (don't forget white balls are quinconx) so I could say the up force is 7.519% of the up force without white balls.

I need a force of 7.5 % and the blue balls move down with 9.31 %

If I move the object down, don't forget each ball win an energy.

[EOW]

Forces change because blue balls can't access all the part between a circle and a line, it depends of the radius of the blue ball