Sum of torque

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The torque from white depends of 2 pressures

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With 2 pressures

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With my method I found the sum of energy at 0 with a gas or with attracted disks (or spheres) but I don't find the sum of energy at 0 with not attracted disks (or spheres).
The sum of forces are at 0 too.

With gas:
from the torque and the force:  0.5*δ*1.1-0.5=0.05
from the volume: 0.005*10*δ=0.05

Only attracted disks:
from the torque and the force: 0.5*δ*1.1-0.516666=0.03333
from the volume: 0.005*10*δ*0.666=0.03333   , I need to take in account the fact that more disks with pressure at 10 moves out than 0 so I used the calculation of the center of gravity of a square triangle

With disks, attracted disks and not attracted disks
from the torque and the force: 0.9535*1.1*δ-1.045*δ=0.0385δ
from the volume: 0.005δ*9.689=0.04844δ

With spheres, attracted spheres and not attracted spheres
from the torque and the force: 0.87*1.1*δ-1.0361333*δ=0.079δ
from the volume: 0.913*0.005δ*10=0.0456δ

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The tube turns clockwise around the red dot and counterclockwise around the black dot.

The difference of volume are the same.

To find the same volume resolve the equation:

(1.1²-1²)/2*pi-(3.1²-3²)/2*pi/x     this gives x at 2.904761    like that the volume is constant and the difference of energy is 2.90895-1.0004*2.904761=0.003

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Like that