Quanta Magnetics Experimental Kits

[nelsonrochaa]

Lol Yes but the result is very good.

[MarkE]

Lol Yes but the result is very good.

It is a good demonstration of the MPP principle.

My judgement of goodness for a PV module MPP controller is first and foremost how much power gets delivered to the load for a given amount of irradiance impinging a PV module of known efficiency.  Since I don't know what PV module you are using or how much light is hitting it or how much power is coming out of your device I can't judge how good the result is.  AC microinverters connected to ~200W nameplate modules these days get 96.5% weighted efficiency which is really good.  At their peak efficiency, they tend to do a smidge over 97%.  If you can get 90% or better from a 10W to 25W module, then I would say that you are doing pretty well.

[nelsonrochaa]

Hi MarkE,
This is not a  PV module MPP controller ,and  the solar panel is not relevant , is only to show the circuit work with lower power wattage source;  in my last video i use a battery .What i want to say is that can be used any source off power  https://www.youtube.com/watch?v=F7EkHm08Te4

What is relevant is the relation between the input power and the output power.

[MarkE]

Hi MarkE,
This is not a  PV module MPP controller ,and  the solar panel is not relevant , is only to show the circuit work with lower power wattage source;  in my last video i use a battery .What i want to say is that can be used any source off power  https://www.youtube.com/watch?v=F7EkHm08Te4

What is relevant is the relation between the input power and the output power.

Yes and no.  In order to maximize the output power from a given source, the load impedance must be the conjugate of the source impedance.  For a resistive source that means matching the resistance.  There are many situations where we don't want to match because it results in unacceptable heating in the source.  For instance if you load a AA alkaline cell with a matched 100mOhm load the cell quickly overheats.

[nelsonrochaa]

Yes and no.  In order to maximize the output power from a given source, the load impedance must be the conjugate of the source impedance.  For a resistive source that means matching the resistance.  There are many situations where we don't want to match because it results in unacceptable heating in the source.  For instance if you load a AA alkaline cell with a matched 100mOhm load the cell quickly overheats.

MarkE ,
The reason of the the great power output of the circuit  is in fact a combination of high current BEMF collected combined with the lower power voltage input source .
If i open the box case of the relay you could see this https://www.youtube.com/watch?v=DfxEAQNOjp0       , but the relay will be fault soon because the air.   

Thanks for your explanation but i think there is things very different.
If you could see my other videos to understand what i try to show .

https://www.youtube.com/watch?v=pf_qUlwSZl0
https://www.youtube.com/watch?v=F7EkHm08Te4

Thanks