The Infinity Transformer? ... ( another Creazy Lenzless idea!! )

[MarkE]

Hi MarkE,

             Sorry for my ignorence, why not possible to use two identical output? because the two output we have  are 180 degree phase shift?? is not this the Lenzless generatore we are looking for?

By the way i really like the drawing!

Good to hear from you!!


Best Regards
luc2010

The transformers all work by Faraday induction.  The direction of the induced currents are all consistent with Conservation of Energy, which is to say that they all conform to Lenz' Law.  If one shorts the output of a transformer, Lenz' Law is still very much at work.

Lenz' Law tells us the polarity of an induced voltage.  A lot of people set-up arrangements where the induced voltage is small and claim that they are getting around Lenz.  That would only be so if the voltage were zero, which they never get it to be, or the voltage were such that the induced currents accelerate rather than resist the changing magnetic field that induces them.  In a transformer this would mean that increasing the primary voltage and therefore magnetizing current from dot to not dot would cause an increasingly negative voltage on the secondary from dot to not dot.  It would mean that as the secondary load impedance is reduced, drawing more and more power, that the primary current would go down drawing less and less power from the source.

ETA:  The attached picture shows an ordinary transformer as it works conforming to Lenz' Law, and if it were to violate Lenz' Law.  A Lenz' Law violation would mean that even light loads would recharge the source through the transformer.  The heavier the load, the greater the recharge rate.  This has never been observed.

[dvy1214]

The configuration does not cheat Lenz.  It just inverts the phase of one of the outputs.

Most likely to see a constant voltage and split amperage 50/50 on the output of the two outputs.

[MarkE]

Most likely to see a constant voltage and split amperage 50/50 on the output of the two outputs.

That doesn't work either.  If one connects two phases that are in sync in parallel then each carries about half the current. It's simpler and cheaper to buy just one transformer with the right ratings.  If one hooks up two phases that are 180 degrees out from each other then each drives the other and no output power is available.

[allcanadian]

I think the easiest way to understand transformer action is to understand that the movement of free electrons(an electric current) in the primary coil produces a changing magnetic field. If the current is increasing the field is expanding and if the current is decreasing the field is contracting and if the electric current reverses direction the magnetic field changes polarity.


The secondary coil has no electrical connection to the primary coil thus it is bound solely to the magnetic field changes produced by the primary current in the primary coil. As such if we want to understand what is happening in the secondary(s) we must first understand what the magnetic field is doing because it dictates the action induced in the secondary.


The best thing a person can do in my opinion is wind your own simple transformer and measure the current and voltage in the primary as it relates to the current and voltage in the secondary because there is no substitute for hands on experience. If you do this it will be etched in your memory and you will not forget the simple rules which apply.


I think people have been reading too many textbooks and an oscilloscope is useless unless we first understand exactly what we are seeing and why it is happening. There are no short cuts here and one must learn to crawl before we can walk let alone run.


AC

[dvy1214]

That doesn't work either.  If one connects two phases that are in sync in parallel then each carries about half the current. It's simpler and cheaper to buy just one transformer with the right ratings.  If one hooks up two phases that are 180 degrees out from each other then each drives the other and no output power is available.

if they are connected to the same load. Other wise, your output is 50/50. 50%+ 50%-