Partnered Output Coils - Free Energy

[tinman]

L1I=L1 inner
L1O=L1 outer
L2O=L2 outer
The current in L2O quickly returns to zero because L1O has switched OFF, AND the tau of L2O is relatively low.
Current flow in L1O and L2O ceases shortly after the FET switches OFF. Both L1O and L2O have small inductances relative to L1I, so they both appear to react more like a resistor because of the low L/R ratio.
As per the explanation above; because L1I is SLOWLY releasing the energy it stored during the On time because of its relatively large L/R ratio.
Even though L1O and L2O are closely-wound (no distance between them), they are somewhat poorly/loosely coupled to each other, and their inductances are small compared to that of L1I (because of their distance to the ferrite core).

The distance of 10mm between L1O and L1I represents a decrease in coupling, but L1I is tightly coupled to a high permeability core giving it a relatively high inductance compared to L2O. It is evident from the test results that the amp-turns from L1O couple much better to L1I than to L2O. I estimate the coupling factor between L1O and L2O is 8 times less (1/r³) than that between L1O and L1I because there is twice the distance between L1O and L2O (L1O to the ferrite core is 10mm, plus another 10mm from the core back to L2O) compared to that between L1O and L1I. Because of the difference in inductance between L1O and L1I, the two make up a step-up transformer.


.99

I understand what you are saying and what you are believing (you do not need to repeat it), but from your responses I can tell that you do not understand what I am saying. What do you mean by "power flowing in both directions" for example? I have not said nor implied that, and it is incorrect to say that. Power is flowing in ONE direction only; towards the load. Don't confuse the direction of power with the direction of voltage or current. I clearly illustrated in one of my last posts how a negative voltage and current ends up being a positive power. Positive power for BOTH cases means power is flowing TO THE LOAD.

L1I is both a reciever and a giver. It recieves power from L1o and gives it to a load. So it takes power in(in the form of a magnetic field),and then it deliveres power to the load-power flowing in-power flowing out==power flowing in both directions. In L1I, current also flows in both directions during 1 cycle-5% in one direction,and 95% in the other.

The current in L1I continues to flow while L1O is OFF because when L1O energized L1I during the ON time, L1I STORED this energy and releases that stored energy at a very slow rate compared to L2O because of L1I's relatively large inductance and L/R ratio. And although the current may appear constant, it is not. It will eventually go to zero, just like L2O does.

Yes,on this we agree. If the current in L1I was constant,then we would have an interesting situation. If the magnetic field strength was constant,we would have no current flow,and if the field is collapsing,we get a slow decrease in current due to the fixed value resistance. So no-the current cant remain constant. But have you ever seen such a stable current flow across a fixed resistance from any transformer where the primary is switched off. Have you seen a transformer built in such a way before?.

All these factors combined result in the effects you are seeing Brad. Not sure I want to spend any more time on this, as I feel it is all fairly clear.

Thanks for your time Darren

[EMJunkie]

Because i can,unlike your self who seems to be nothing more than a keyboard jockey.
And it's a good guess that your one of my resident thumb downer's on my youtube channel lol. Well as long as im keeping you busy

Yes, I wish the KBD Jockey's would do their part and join in - Really comments from these people are very much more appreciated if they understood a little more about what really is going on!

Time to do some work people! Off that lazy Behind!

   Chris Sykes
       hyiq.org

[tinman]

Like the ice skater that spins on the spot , the more she closes in the faster she goes??
artv

Is it just not a matter of when the primary is cut ,the field needs to collapse?
As it collapses , it closes in on itself, as it closes in it gains momentum, just like water going down a drain?

Yes indeed. And the closser it gets to the center of the core,the more energy it has(higher momentum),and the longer the field time constant.

FG -frequency generator?
SG - signal generator?
Aren't they the same?

I would think so,but SG is more fitting.

[poynt99]

But have you ever seen such a stable current flow across a fixed resistance from any transformer where the primary is switched off. Have you seen a transformer built in such a way before?.

No offense Brad, but there is nothing remarkable about the effects you are seeing and that have been reproduced. This is standard stuff.

Thanks for your time Darren

Although I fear it has been in vain, you're welcome

[tinman]

No offense Brad, but there is nothing remarkable about the effects you are seeing and that have been reproduced. This is standard stuff.
Although I fear it has been in vain, you're welcome

It is sad to hear that Darren,as im sure you are able to view the video i posted in the other place.