Partnered Output Coils - Free Energy

[poynt99]

Do you ever check the references at the bottom of a Wiki page?

Most often the Wiki articles are regurgitations of these references, or at the very least they are based on them. If you do some homework (i.e. searching other pages on near and far field), you will find the Wiki articles I linked quite accurate.

[MagnaProp]

In the pic below,the red arrows show conventional current flow direction when a current is supplied by a power source to the coil. The red + and - show the voltage polarity. The blue arrows show the current flow direction when the supply current to the coil is broken,and the blue + and - show the voltage polarity. So you see,the current will continue to flow in the same direction when the current supply to the inductor(coil) is broken(disconnected),but the voltage polarity will invert.

Thought about it some more and can't figure out why the current would want to go in the direction of the big red arrows I added if the diode wasn't there. I don't see why it wouldn't keep flowing clockwise if just a short was there instead of the diode. If current is already going in a clockwise direction when power is applied, why wouldn't it keep going in that direction even with power removed, since an object in motion wants to stay in motion unless some other force causes it to change. What other force would cause the current to switch directions and flow counterclockwise if the diode wasn't there?

Very interesting. Thanks for the info. I did not know it was possible to get the same current flow direction and thus the same magnetic field, from different voltage potentials. I will have to think about this some more. Thanks again.

With a dead short and no diode present, I still see the current flowing in the correct direction, clockwise, so I don't know why we need the diode? Would the current in a dead short start to bounce back and fourth like self oscillation so we need the diode to keep it all moving in only one direction?

[tinman]

TinMan-So,in the video below,are you saying that the current flowing through the secondary coil is being produced by an E field only?,as the magnetic field/magnetic flux is contained within the core.

https://www.youtube.com/watch?v=x-EuPGl8JjE
Poynt-Yes.

TinMan-Can you also post a paper or any information that shows a changing/varying E fields that has no magnetic field associated with it.

Poynt-If I said that, yes. Since I did not say that, no.


So i ask if the current in the secondary in that video is being produced by an E field only,and clearly stated that the magnetic field/magnetic flux is being contained within the core-->and you say yes.
Then i ask you to post a paper or some sort of proof that a varying E field has no magnetic field associated with it,and you say-->i never said that.

You then go on to say that the E field has a H field as well.
Well,the H field is a magnetic field,and so that can only mean that the secondary in that video is NOT producing current flow from the E field only.

So,if there is a H field (the determined magnetic field strength) with that E field,then all the magnetic field is not contained within the core,where as the B field is only that that determines magnetic flux density.

As i said,a varying electric field cannot induce an EMF or current flow through a conductor,as a varying electric field alone dose not exist. Any varying E field(be it a near or far field) also has a magnetic field.

[poynt99]

I think what Brad is asking for is info on how it is the E field in the closed 'transformer', not the mag field, that induces the secondary from the primary.

Like a book or paper that states this in 'transformer' theory and or design.

Because that was what I was about to ask.

Mags

If you look up the equation for induced emf, you will find that it is the line integral of the E field. The line integral of the E field is equal to the rate of change of the flux (phi) with respect to time.

Something like: emf = Integral E.dl = -d(phi)/dt

So this illustrates how the changing flux, induced E field, and resulting emf are all linked.

Most people incorrectly believe that the flux alone induces the emf because the emf is computed directly from the flux (phi). However, the flux induces an E field, and its the E field that induces the emf in the coil.

[poynt99]

I have a toroid I am going to wind and do some testing with an analog hall sensor.

Are there any tests we can do the measure that there is an E field around the core, even in areas that are away from the windings?  For example, if I make a large air core coil, say square, flat sides, and set it up where one flat side is fixed against the outer circumference of the transformer core, will that air core coil be induced by the actions of the transformer just as good(or at all) as if the air core coils wires went through the hole of the core?

Mags

The E field goes around the axis of core. In order to induce an emf with another coil it also has to go around the core, as shown in my diagram. The E field and core windings have to be essentially the same.

If your secondary coil is just pressed up against the toroid (or square) core like your first rendering above, there will be little to no induction. The second rendering will produce an emf.

The test you can perform to detect the E field is to use several turns of wire (in a big loop if you want), and loop it with the core.