Partnered Output Coils - Free Energy

[minnie]

   Good question Tinman,
           Permanent magnet will do work but when you think about it
your hand must always be involved.
    Magnet may attract iron bar but you ALWAYS have to put energy
in to separate the pieces.

[tinman]

MileHigh

You have to understand that when you are discussing something then two viewpoints mean a two way street for both viewpoints.  You allege that I am trying to force my view on you.  But if you object to what I say then you are trying to force your view onto me.  Don't you get that?

Um-no,i dont get that.
So let me get this straight. You say there are two view point's. You believe that i think you are forcing your view on to me . Then if i object to what you believe,then i am trying to force my view onto you
No and NO. I believe that everyone has a right to there own view,but i do object to others trying to change mine.

Look, you said, "Flux velocity through the secondary exceeds that of what the primary projects."  That is nonsense.There is just a B field, and magnetic flux density and total magnetic flux, and all of the coupling effects are determined by the rate of change of magnetic flux with respect to time.

Im guessing that you believe that reactive power on a primary winding of a transformer can not be converted to real power through the secondary .
You still have no explanation  as to why the inner secondary(which is a 1:1 turn ratio to the primary)has double the open voltage to that of the primary. Your opposite spin theory dose not hold up when we are measuring open voltages,and no current flowing through the secondary. The rate of change in magnetic flux density is not the same between the inner core and outer core. As the inner core is far more permeable than the outer core,the flux density rises at a far greater rate than that of the less permeable outer core.

It seems you are making up your own definitions on the fly.  That has severe limitations.

I am yet to see your beliefs explain the above.

You are going to go ahead and ignore some of the stuff that I say, that's your prerogative.  But like I said before, when all is said and done, if you are wrong after all of your testing is done and the real experts around here give you guidance and suggestions that you listen to, then state your conclusions and account for your theories and state if they were right or wrong.

I would expect the same from you MH.

If not you get people saying things like, "The 'radiant energy spike' is voltage with almost no measurable current."  And after all this time I am pretty sure that you know that by definition the "radiant energy spike" is a pulse of current at a certain voltage.  That's the kind of B.S. that we all want to avoid.

Indeed.
There is so much more to come yet MH. Now we start to try and prove this negative resistance-and we have some very bright minds working on this ATM.
Below is a scope shot from some of my latest testing !!using non inductive resistors!
The blue trace is across a 1ohm (non inductive)CVR,and the yellow trace is across both the CVR and primary. I also put up the math trace for hoots. The math trace is set to 500mV per division,as we are using a 1ohm CVR,then the math trace show's 500mW's per division-but im sure you know that. But it gets better MH,so we will see how we go.

[tinman]

   Good question Tinman,
           Permanent magnet will do work but when you think about it
your hand must always be involved.
    Magnet may attract iron bar but you ALWAYS have to put energy
in to separate the pieces.

When you separate the two,then you are the one doing the work to miss align the magnetic domain's. Once the domains are aligned,they want to stay aligned-the iron wants to stick to the PM. When you supply the work to separate the iron from the magnet,you are supplying the energy that returns those domains back to there original state. The work was already done by the PM to align the domain's,so as the iron became attracted to the PM.

[tinman]

Here is a little something else i have done-in case it is of any importance.
Below you will see a scope shot that has a green trace in it-->best i could do with windows paint,but you get the general idea.
In the two shots below,i am triggering from the blue channel(channel two),which is across the 1 ohm CVR.
In the 1st scope shot,the yellow trace is across the CVR and primary coil. In the second scope shot,the yellow trace is now across the inner secondary that has a 10 ohm carbon resistor across it.

So i traced the green on the first scope shot,so as it is the same as the trace across the 10 ohm/inner secondary combo-->the yellow trace on the second scope shot. This way we can see what the inner secondaries power phase relationship is with that of the primaries voltage and current phases. I made sure the secondary was in phase with the primary at 100HTz,and then wound the frequency up to 5MHz.
The green trace would there for be 100mV per division.

[picowatt]

Tinman,

As you continue to perform tests, consider measuring and making note of the open circuit voltage of your FG.  Measure directly at the FG's BNC.  Also make a measurement of the FG output while connected to your circuit (also directly at the FG's BNC). The use of a BNC Tee at the FG output would provide a convenient test point. 

Measuring directly at the FG's output BNC reduces lead inductance issues.

Knowing the FG's output voltage with and without your circuit's load will allow additional power calculations (I assume your FG out is 50R).

PW

(edited to be more specific as to where/how to measure)