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Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

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0 Members and 220 Guests are viewing this topic.

Bob Smith

Thanks for this info, Chris.  Just one thing I'd like to focus on in my reply:
QuoteAs the load on the machine increases, the volt-ampere product increases.

A raised load will have an increased volt-ampere draw on a system.  When my vacuum cleaner moves from a smooth floor and onto a deep pile carpet, the extra drag on the beater bar draws more charge:  the wires heat up as extra amperage is pulled to accommodate the demands of the load. 

What if the load is a high impedance coil in an oscillating circuit.  Higher impedance will also mean more opposition to each impulse of charge (Lenz' Law) will it not?  From whence does this opposition come? My belief (one shared by a number of others) is that it comes from outside the coil - namely from the dielectric realm.  From this standpoint, if we want to draw more ambient charge into a system, we are better off with higher, than lower impedance coils.  And again, from this standpoint, a pulsed coil - especially a high impedance coil - is actually a kind of open system pump, which can be primed with an initial charge to draw in a responding charge from the dielectric (again, Lenz' Law).

It stands to reason partnered output coils are going to pump even more energy from the dielectric realm (again, by the logic of Lenz' Law).
Bob

EMJunkie

Hi Bob,

Trying to reply for all levels of knowledge, so please forgive me if this is a little simple.

Quote

As the load on the machine increases, the volt-ampere product increases.


This is a Golden observation of yours!!!

Volt-Ampere Product will be determined by several factors:

   1: Output Coil Impedance.
   2: Time Rate of Change of the Magnetic Field - AKA Frequency
   3: Magnetic Field Strength...

Forgive me if I have missed some, I am sure I have, but for now this covers what I need to cover.

Output Coil Impedance, Symbol: Z, this is perhaps the most important factor to consider! Why? Because it changes with the Field Strength!!! The Impedance of the Coil is seen in two parts: Real Resistance/Imaginary Resistance. This may be written as 1j+20, or 1j-20 - Where 1 = Real Resistance and 20 = Imaginary Resistance as an example.

Real Resistance is the Coils DC Resistance.
Imaginary Resistance is the Coils Inductive, or Capacitive Resistance. Known as XC for j- or XL for j+

Please remember, I dont have all the answers, I am still learning also, but...

Imaginary Resistance is the part I believe to be changing with the change in Magnetic Field. This is the reason, as far as I can tell, why the Volt-Ampere Product increases! As the Load Resistance is lowered, more Current (I) flows in the Coils. Remembering that Current is analagous to the Magnetic Field, they are one and the same thing, as a Current flows, Charges Moving, a Magnetic Field is Concentric around the Horizontal plane of movement. 90 Degrees to the direction of movement.

This is seen in my experiment: Guidelines to Bucking Coils - Page 14 - I show how the Coil's Impedance can dramatically change depending on the Magnetic Field.

Quote from: Bob Smith on December 29, 2015, 10:48:45 AM

What if the load is a high impedance coil in an oscillating circuit.  Higher impedance will also mean more opposition to each impulse of charge (Lenz' Law) will it not?


Of course, the answer to these question's depends entirely on the device and how it is configured, but generally, the Higher the Load Impedance, the less Current flowing in the Partnered Output Coils, the Less Magnetic Field Strength and the less Total Feed Back to Separate Charges from the Conductors. Volt-Ampere Product will be Less! So typically this would be considered undesirable for some systems. I would like to quote:

Quote

The VTA "likes" to always see a minimum load of 25 watts.

Ref: FLOYD SWEET'S VTA UNIT by Walt Rosenthal



This Quote was one of my biggest clues!!!

After reading your post a few times, trying to see through your eyes, I feel there may be something I should suggest: I think this is critical

Quote

Partnered Output Coils, or any coil that has an Electromotive Force impressed on it should be thought of as a Battery, instead with an AC Output, or an Electric "Generator" - Reversing the Characteristics of the Coil if we were to look at the Characteristics of the Coil when we apply a Voltage and thus a Current to the Coil.


By this, I mean, Each Coil in the Partnered Output Coils has become a Source of Charge, a Battery, or an Electric "Generator", if you like. The Conductors themselves, are Interacting together to Separate Charges inside the Coil Conductors and this will happen because "magnetic effects vary on the square of the current"

The Magnetic Field B = μ0I/2πr but for a Coil with N number of turns, the Magnetic Field B = μnI

So, lets have a look at this: (for simplicity μ = 1)

Quote

B = 1μ x 10n x 1I = 10Gauss
B = 1μ x 10n x 10I = 100Gauss


The turns stayed at 10. Current went from 1 Amp to 10 Amps, but the Magnetic Field went from 10 to 100, that means, the Current, 102 = 100Gauss.

Quote from: Bob Smith on December 29, 2015, 10:48:45 AM

From whence does this opposition come?


Yes, the Opposition is "Lenz's Law", Lenz's Law is a Changing Magnetic Field in Time that Opposes the Source Magnetic Field. Note the Key Words: Lenz's Law is a Changing Magnetic Field in Time

Lets look at our understanding here:

Quote

A dielectric material (dielectric for short) is an electrical insulator that can be polarized by an applied electric field.

Ref: https://en.wikipedia.org/wiki/Dielectric


In and around the Insulating Material, in our case, mostly it will be the Enammel Layer that the Copper wire is Insulated with, Lenz's Law, its associated Magnetic Field will be present when the Charges are flowing in the Coil Conductor, thus Concentric Magnetic Field Lines surround the Wire. Where ever there is a Magnetic Field, we already know this can influence Charged Particles.

Weather energy is extracted from this area I do not know for sure and I can not prove or dssprove it. This is where the Heavyside Poynting Vector says some energy can come from but not all. See below Image:

Quote

It [the energy transfer flow] takes place, in the vicinity of the wire, very nearly parallel to it, with a slight slope towards the wire... .  Prof. Poynting, on the other hand, holds a different view, representing the transfer as nearly perpendicular to a wire, i.e., with a slight departure from the vertical.  This difference of a quadrant can, I think, only arise from what seems to be a misconception on his part as to the nature of the electric field in the vicinity of a wire supporting electric current.  The lines of electric force are nearly perpendicular to the wire.  The departure from perpendicularity is usually so small that I have sometimes spoken of them as being perpendicular to it, as they practically are, before I recognized the great physical importance of the slight departure.  It causes the convergence of energy into the wire.


I am undecided on these ideas/theories. Too much like Energy from Fresh Air. Today we know from Quantum Electrodynamics that Electron - positron annihilation into neutrino - antineutrino can occur and we know the Sun does Emmit Neutrinos, and they can penetrate the Earth (Perhaps one of my favorite documentary's), so the Heavyside Poynting Vector may hold true to a point.

I much prefer the Energy-Mass Equivalent Theory as there is a TON of supporting evidence!!! This can be seen in the following Videos:

Electrical Energy 101 - Faradays Law of Induction - Part 1
Electrical Energy 101 - Faradays Law of Induction - Part 2
Electrical Energy 101 - Faradays Law of Induction - Part 3

How Magnets Produce Electricity - 1954 US Navy Training Film

Lets not forget, if the Terminals of an Electrical "Generator" were Insulated, we would not be able to power a Load, we have to bare back, strip off the Insulation to Power a Load!!! Electrical Enegy Flows in the Conductive Material. <<-- What does this really mean?

I think that there is an overall point to be seen here. Some time back I built one of Steve Ward's Ward Force Generator's, this device is quite a smart device! Mine did not reach beyond Unity, but was a great learning apparatus! The Magnetic Field Interactions in this device show that a Magnetic Field can Support Itself

   Chris Sykes
       hyiq.org

cdsharp

Hi, Chris! I'm trying to send you a message on hyiq contact page, but something crashes.

Bob Smith

Thanks for this, Chris. I keep reading thru it - there's a lot there, and yet once grasped, I think it's a clear way of understanding a coil's performance with regard to a load.
Bob

Edit:  OK. I see when I posted that you added a few more things to the last post, Chris. Here is something I posted on another forum, which perhaps gives a slightly different take on the same phenomena you are describing in the last part of your post. I think (hope) I'm using simpler, less refined and less differentiated terms than you are, but hopefully on the same page... please let me know what you think if you have a chance
QuoteAccording to Tesla, there is potential difference present between the turns in a coil; there is storage of charge, or capacitance. See his patent, https://teslauniverse.com/nikola-tesla/patents/us-patent-512340-coil-electro-magnets Coil for Electromagnets for details. Because of this potential difference between turns, there must also forces of attraction between them; and taking this logic one step further, perhaps interaction with the dielectric along the coil between the windings, in a manner similar to that which occurs at the bloch wall or dielectric plane at the coil's midpoint.

What could this mean? If the dielectric is interacting with the coil between each of the windings as well as at the overall midpoint, then these areas are points at which charge enters the coil from the dielectric to produce the Lenz' Law (opposing spike) effect. IOW, Lenz' Law is the dielectric's response to an initial pulse in the coil.
Bob

EMJunkie

Quote from: Bob Smith on December 29, 2015, 08:20:25 PM
Thanks for this, Chris. I keep reading thru it - there's a lot there, and yet once grasped, I think it's a clear way of understanding a coil's performance with regard to a load.
Bob

Edit:  OK. I see when I posted that you added a few more things to the last post, Chris. Here is something I posted on another forum, which perhaps gives a slightly different take on the same phenomena you are describing in the last part of your post. I think (hope) I'm using simpler, less refined and less differentiated terms than you are, but hopefully on the same page... please let me know what you think if you have a chanceBob


Hi Bob,

Sorry, I do somtimes edit posts if I feel I can better them. It is a long post that one!!! Many hours of study in there for some.

I believe youre referring to Distributed Capacitance

All Coils will display a certian value of Distributed Capacitance.

   Chris Sykes
       hyiq.org